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Topic: no match in == from array against string (Read 415 times) |
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edwardgeorge
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no match in == from array against string
« on: Mar 13th, 2003, 7:12pm » |
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In some code i have, an incoming string is passed to a 'check' function to see if it is location info (in this example, there is also other types), this is defined by the second word.
So, check() splits the string at " " (spaces) amd checks the second word(#1) against "Location", printing out the first word if it matches.
else it prints out "no location info -" then the word it tried to match against "Location" then a forward slash(to make sure there is no trailing whitespace)
see the following code...
Code:
void check(String l){
println("checking:"+l);
String[] a=l.split(" ");
if(a[1]=="Location"){
println("found:"+a[0]);
}else{println("no location info -"+a[1]+"/");}
}
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heres what it results in
Code:
checking:TMale0 Location -300 200 400
no location info -Location/
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it seems it is not matching the second word in the array(in this case Location) against Location.
Wha?
What is going on?
Thanks for any light you may shed.
Ed_
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Ed, Suppose, Nottingham, UK
http://www.suppose.co.uk
http://ed.suppose.co.uk
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_martin
Guest
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Re: no match in == from array against string
« Reply #1 on: Mar 14th, 2003, 12:59am » |
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Code:void check(String l){
println("checking:"+l);
String[] a=l.split(" ");
if(a[1]=="Location"){
println("found:"+a[0]);
}else{println("no location info -"+a[1]+"/");}
} |
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_martin
Guest
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Re: no match in == from array against string
« Reply #2 on: Mar 14th, 2003, 1:01am » |
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argh. sorry about the previous post. accidentally pressed the 'post' button. here...
Code:void check(String l){
println("checking:"+l);
String[] a=l.split(" ");
if(a[1].equals("Location")){
println("found:"+a[0]);
}else{println("no location info -"+a[1]+"/");}
} |
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_martin
Guest
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Re: no match in == from array against string
« Reply #4 on: Mar 15th, 2003, 6:25am » |
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btw, s.split(String s2) is the java way of doing it. splitStrings(String s, String s2) is the processing way of doing it.
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fry
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Re: no match in == from array against string
« Reply #5 on: Mar 15th, 2003, 1:51pm » |
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on Mar 15th, 2003, 6:25am, _martin wrote:| btw, s.split(String s2) is the java way of doing it. splitStrings(String s, String s2) is the processing way of doing it. |
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yeah, and i'd remove splitStrings() except that split() is only available in jdk 1.4, which isn't running in most browsers (or at all on macos9).
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