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hi guys..
i see this tutorial and display image. http://processing.org/examples/loaddisplayimage.html
but where the directories file image ?
Answers
sorry i mean. if i have a image file . example "abc.jpg" ... where i was save the "abc.jpg" to can access from processing ?
I've already answered that. Just use dataPath("")! X_X
For a file called "abc.jpg", use ->
loadImage( dataPath("abc.jpg") );
.:( sorry my internet was slow down. i think nobody here comment this post.
so.. if use dataPath("") i can save my image file to anywhere directories right ? and the processing will find self the image location ? CMIIW
No, it's not it! [..] Function dataPath("") gives the path of where we put program's resources!
It means the subfolder "/data"! 3:-O
Actually,
loadImage("abc.jpg")
is enough, since by default it load it from the dataPath().lovelyazka, you have to put the images you want to load in a folder named
data
inside the sketch folder (the one where the .pde file is saved).