How do I prevent the [] to appear (using strings)?

dawnspectraa

So I'm trying to get some keyboard input. Right now, I know that the code to delete the last letter from a string is:

if (key == BACKSPACE) 
  {
  written=written.substring(0,written.length()-1);
  }

But I'm showing what's being typed in the window. When I press BACKSPACE, in the window appears the [] symbol. I don't want it to appear and, instead, I want it to be replaced by the new letter the user types.

How to?

GoToLoop

Can't figure out any problems from what you've posted so far.
btW, a working online example: (*)

http://studio.processingtogether.com/sp/pad/export/ro.9Zo$UbIWYZEDR/latest

Chrisir

yes, please post your entire code

btw

you should say

written = written + key;

only when it's not backspace

if (key == BACKSPACE)
  {
  written=written.substring(0,written.length()-1);
  }
else {
   written = written + key;
}

Greetings!

Chrisir

here....

// 

String written = "";

void draw () {
} // func 

//

void keyPressed() {
  //
  if (key == BACKSPACE)
  {
    if (written.length()>0)
      written = written.substring(0, written.length()-1);
    // println (  key + "  -  "  + int (key));
  }
  else {
    written = written + key;
  }
  println ( written );
  //
}
//

dawnspectraa

Sorry. Well, basically my whole code is this (variables are in spanish):

String[] adjetivos={"bonita","fea","hermosa","fantasmal","kawaii","sucia","inteligente","pendeja"};
String adj="... ";
int adj2=0;
String nombre="";
String escrito="";
Boolean input=true;
Boolean todavia=true;

void setup()
{
  size(800,600);
  background(0);

  textSize(20);
  textAlign(CENTER);
}

void keyPressed()
{
  if (key == '\n')
  {
    nombre=escrito;
    input=false;

    int adjR=int(random(adjetivos.length));

    if (adjR == adj2)
     {
       adjR=int(random(adjetivos.length));
       adj2=adjR;
     }
     adj=adjetivos[adjR]; //adjetivos[int(random(adjetivos.length))];
     println(adj);
     }
     else
     {
       if (input)
       {
       escrito+=key;
       }
     }
}

void draw()
{
  background(0);

  if (input)
  {
    text("Escribe tu nombre: ",width/2,height/2-100);
    text(escrito,width/2,height/2);
  }

  if (!input)
  {
  text("Eres muy "+adj+", "+nombre,width/2,height/2);
  }
}

What I'm trying to do is that when hitting BACKSPACE, it removes the last letter. Like normally we use it. That's all. I know how to delete the last letter from a string (using subtstring), but I don't want to see the [] symbol appear. Try it out.

GoToLoop

It's somewhat useless posting your code when the bugged part isn't included there! :-w
Besides, there are some indentation inconsistencies. Better use CTRL+T inside Processing's IDE! :-\"

Anyways, @Chrisir has already posted a snippet example on how to do it! And I've posted an online running example too!

http://studio.processingtogether.com/sp/pad/export/ro.9Zo$UbIWYZEDR/latest

Why don't try to adapt the working algorithms to your own program? :>

PhiLho

Your code doesn't use BACKSPACE, that's why you see the rectangle, showing an interpretation of the backspace char...
Likewise, don't use '\n', use ENTER instead.

dawnspectraa

thanks