"Found a { that's missing a matching }" but there is none.

TheZipCreator

Or at least I can't find any. So this code doesn't seem to work, and it's giving the error stated in the title. I can't find any unbalanced braces Here's my code

ArrayList<String> references; //Names of vars
ArrayList<Object> results; //What the vars equal
ArrayList<ArrayList<String>> tokens; //The tokens
int token; //What token it's on
int line; //The line it's on

void setup() {
  references = new ArrayList<String>();
  results = new ArrayList<Object>();
  tokens = new ArrayList<ArrayList<String>>();
  String[] file = loadStrings("code.sba");
  for(int i = 0; i < file.length; i++) { //Get Tokens
    file[i] += " "; //Make sure there's no missed tokens
    ArrayList<String> temptokens = new ArrayList<String>(); //The tokens in this line
    String currtoken = "";
    boolean instring = false;
    for(int j = 0; j < file[i].length(); j++) {
      char c = file[i].charAt(j); //Get char
      if(c == '"') {
        instring = !instring; //Set that it's inside a string
      }
      if(!instring) {
        if(c != ' ') { //Find a token
          currtoken += c; 
        } else {
          temptokens.add(currtoken);
          currtoken = "";
        }
      } else {
        currtoken += c;
      }
    }
    tokens.add(temptokens); //Add the token that was just found to the tokens in this line
  }
  printArray(tokens);
}
void settings() {
  size(200, 200);
}
void draw() {

}

koogs

Edit post, highlight code, press ctrl-o to format.

Actually, if you hit Ctrl-t in the processing editor it'll indent the code nicely and it'll be easier to see the problem.

TheZipCreator

Ok I fixed the formatting, but all CTRL+t did is move some parenthesis one char to the right, it didn't really make anything that more easier to find

Chrisir

IN general it helps a lot

Also place cursor next to a bracket its partner will be highlighted - helps also to check

Leave empty lines between functions and after for-loop-sections {}

Chrisir

I got some questions

Before setup ()

ArrayList references;

should be

      ArrayList <String> references; 

For the others too

Not sure how to define an ArrayList of ArrayList, maybe easier to capsule the latter one in a small class

TheZipCreator

I know that putting your cursor over a bracket highlights the corresponding bracket, but I can't seem to find any brackets that seem out of place

Chrisir

Sorry my post was bad because I write on my phone.

I corrected it.

Apologies.

Chrisir

Hit F5 to reload page

koogs

The double quote on line 19 might be confusing it.

Chrisir

this works though:

char c = '"';

if (c == '"') {
  println("here");
}

Chrisir

line 10 looks suspicious too

but this test works:

ArrayList<String> references; //Names of vars
ArrayList<Object> results; //What the vars equal

ArrayList<ArrayList<String>> tokens; //The tokens


void setup() {

  tokens = new ArrayList<ArrayList<String>>();

  tokens.add ( c1() ); 

  printArray(tokens.get(0).toArray());
}

ArrayList<String> c1() {

  ArrayList<String> c_ = new ArrayList();

  c_.add("apple");
  c_.add("banana");
  c_.add("pie");

  return c_;
}

I guess we are looking at other things that causes the error besides missing } e.g. wrong ; or so....

Chrisir

koogs was right, it's line 19

you want

     if (c == '\"') {

with \

apologies, not sure why my mcve did work and yours not

this works too:

char c = '\"';

if (c == '\"') {
  println("here");
}

koogs

what do i win?

Chrisir

You were right!

If we were in the same town you'd get a bottle of red wine ;-)

TheZipCreator

Well that was the issue, it said earlier that '\"' was an invalid character constant, but now it is valid, but anyways that was the issue

Chrisir

I found out by putting huge sections of the code in comments and check if the error still appears to narrow it down