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Could you tell me how to change part of the following code from the processing website(https://processing.org/examples/forceswithvectors.html) so that the balls move from bottom to top rather than from top to bottom?
// Five moving bodies
Mover[] movers = new Mover[10];
// Liquid
Liquid liquid;
void setup() {
size(640, 360);
reset();
// Create liquid object
liquid = new Liquid(0, height/2, width, height/2, 0.1);
}
void draw() {
background(0);
// Draw water
liquid.display();
for (Mover mover : movers) {
// Is the Mover in the liquid?
if (liquid.contains(mover)) {
// Calculate drag force
PVector drag = liquid.drag(mover);
// Apply drag force to Mover
mover.applyForce(drag);
}
// Gravity is scaled by mass here!
PVector gravity = new PVector(0, 0.1*mover.mass);
// Apply gravity
mover.applyForce(gravity);
// Update and display
mover.update();
mover.display();
mover.checkEdges();
}
fill(255);
text("click mouse to reset", 10, 30);
}
void mousePressed() {
reset();
}
// Restart all the Mover objects randomly
void reset() {
for (int i = 0; i < movers.length; i++) {
movers[i] = new Mover(random(0.5, 3), 40+i*70, 0);
}
}
/**
* Forces (Gravity and Fluid Resistence) with Vectors
* by Daniel Shiffman.
*
* Demonstration of multiple force acting on bodies (Mover class)
* Bodies experience gravity continuously
* Bodies experience fluid resistance when in "water"
*/
class Mover {
// position, velocity, and acceleration
PVector position;
PVector velocity;
PVector acceleration;
// Mass is tied to size
float mass;
Mover(float m, float x, float y) {
mass = m;
position = new PVector(x, y);
velocity = new PVector(0, 0);
acceleration = new PVector(0, 0);
}
// Newton's 2nd law: F = M * A
// or A = F / M
void applyForce(PVector force) {
// Divide by mass
PVector f = PVector.div(force, mass);
// Accumulate all forces in acceleration
acceleration.add(f);
}
void update() {
// Velocity changes according to acceleration
velocity.add(acceleration);
// position changes by velocity
position.add(velocity);
// We must clear acceleration each frame
acceleration.mult(0);
}
// Draw Mover
void display() {
stroke(255);
strokeWeight(2);
fill(255, 200);
ellipse(position.x, position.y, mass*16, mass*16);
}
// Bounce off bottom of window
void checkEdges() {
if (position.y > height) {
velocity.y *= -0.9; // A little dampening when hitting the bottom
position.y = height;
}
}
}
/**
* Forces (Gravity and Fluid Resistence) with Vectors
* by Daniel Shiffman.
*
* Demonstration of multiple force acting on bodies (Mover class)
* Bodies experience gravity continuously
* Bodies experience fluid resistance when in "water"
*/
// Liquid class
class Liquid {
// Liquid is a rectangle
float x, y, w, h;
// Coefficient of drag
float c;
Liquid(float x_, float y_, float w_, float h_, float c_) {
x = x_;
y = y_;
w = w_;
h = h_;
c = c_;
}
// Is the Mover in the Liquid?
boolean contains(Mover m) {
PVector l = m.position;
if (l.x > x && l.x < x + w && l.y > y && l.y < y + h) {
return true;
} else {
return false;
}
}
// Calculate drag force
PVector drag(Mover m) {
// Magnitude is coefficient * speed squared
float speed = m.velocity.mag();
float dragMagnitude = c * speed * speed;
// Direction is inverse of velocity
PVector drag = m.velocity.copy();
drag.mult(-1);
// Scale according to magnitude
drag.setMag(dragMagnitude);
return drag;
}
void display() {
noStroke();
fill(127);
rect(x, y, w, h);
}
}
Thank you!
Answers
First of all you have to reset where the Movers start, the starting position is set in reset with this line.
movers[i] = new Mover(random(0.5, 3), 40+i*70, 0);
where 0 is the Y position. Which means you have to change the Y position to height instead of 0.
Next up you want to invert the gravity so everything moves up instead of down which is done by inverting the gravity value in this line
PVector gravity = new PVector(0, 0.1*mover.mass);
so
0.1*mover.mass
becomes-0.1*mover.mass
and last but not least you have to change where the Mover stop which is done with these lines
Instead of checking when a mover is above height (position.y > height) you check if its below the bottom of the screen (position.y < 0) after which you reset the position.y to the bottom instead of the top so
position.y = height;
becomesposition.y = 0;