How to generate unique random number

alohaman

How to generate unique random number from range 1 - 10.

Chrisir

Fill an array with those

Shuffle the array

Display the first number, then the 2nd number etc. from this array

alohaman

I don't know how to type that syntax and If I need 5 numbers. How I should type ?

GoToLoop

IntList il = IntList.fromRange(1, 11);
il.shuffle(this);
il.resize(5);
println(il);
exit();

jeremydouglass

@alohaman.

I need to do something with a list of Integers.

• IntList: https://processing.org/reference/IntList.html

...only in a random order. "Shuffled."

• IntList.shuffle(): https://processing.org/reference/IntList_shuffle_.html

Start by using that example sketch right there in the reference.

This is what to do if you are working with a list (like a deck of cards, with each card occurring once.

7, 8, 2, 5, 1, 3, 0, 9, 4, 6

If instead you were trying to but instead like rolling a 10-sided die (and each value is independent)

7, 7, 6, 3, 0, 7, 2, 6, 8, 1

...then you can do that like this:

int x = (int)random(10);
println(x);

koogs

use (int)random(1, 11) to get integers from 1 to 10

alohaman

Thanks everyone attend my post

I use shuffle and list of integers. It can work to random 5 numbers. But how can I take those numbers to separate for use with others.

jeremydouglass

But how can I take those numbers to separate for use with others.

I don't understand this sentence.

Can you show your code, and explain exactly what you are trying to do?

Is your problem this?:

Q. "I made an IntList. How do I get a number from the IntList?"
A. "Read the IntList reference! It shows an example."

• https://processing.org/reference/IntList.html

The entry has an example sketch that shows how to use IntList.get(), copy the value into an int, then draw it as text.

alohaman

@jeremydouglass Oh sorry,to not answer you. Now I got a answer. "But how can I take those numbers to separate for use with others." that sentence ,I mean

IntList il = IntList.fromRange(1, 11);
il.shuffle(this);
il.resize(5);
println(il);
exit();

If I use that code, How can I separate them to be unique number as such as B[1] , B[2] , B[3] and B[1] = shuffle first number. B[2] = shuffle second number. B[3] = shuffle third number. and any number. for use with others function. I 'm so sorry from my english ,if u don't understand.

and this is my code that I got a answer.

import java.util.Random;
int[] number = new int[5];
int count=0;
int num;
Random r = new Random();
while(count<number.length){
    num = r.nextInt(10);
    boolean repeat = false;
    do{ //1
        for(int i=0; i<number.length; i++){ //2
            if(num == number[i]){//3
                repeat = true;
                break;
            } //3
            else if(i == count){ 
                number[count] = num;
                count++;
                repeat = true;
                break;
            }
        } //2
    }while(!repeat); //1

}

for(int j = 0; j < number.length; j++){
    System.out.print(number[j]+" ");
}

Credit : https://stackoverflow.com/questions/33636887/generating-10-random-numbers-without-duplicate-with-fundamental-techniques

jeremydouglass

@alohaman --

Read the IntList reference!

Read the IntList reference!

https://processing.org/reference/IntList.html

The example at the top shows how to get a specific number -- using get()!

The entry on get() right below says "get(): Get an entry at a particular index"

Read the IntList reference!

alohaman

@jeremydouglass hah, I got it. Thanks for repeat that for me.