surface.setSize and a 2D array

jaspervanblokland

Hi All

I am working on a surface.setSize with multiple sizes. Now i know how to do that. Inside the 'surface.setSize', i wanne use a 2dimensional array, but that doesnt work. I don't know why.

int cols = 400; int rows = 500;

int[][] size = new int[cols][rows];

void setup() { size(100, 100); surface.setResizable(true); }

void draw() { background(2); if (key == '1') { surface.setSize(size[][]) ; } else if (key == '2') { surface.setSize(size[][]) ; } }

Can anyone tell me the problem.

Tnanks@!

kfrajer

Not sure why you are using a 2D array. Try this next code.

Kf

void setup() { 
  size(100, 100); 
  surface.setResizable(true);
}

void draw() { 
  background(2); 
  if (key == '1') { 
    surface.setSize(200,200) ;
  } else if (key == '2') { 
    surface.setSize(500,500) ;
  }
}

jaspervanblokland

Thank you for your comment. I excually already knew how to do this. I was just wondering if i could make a 2D array of two values for inside a setSize

kfrajer

You variable size has 400 cols and 500 rows, for a total of 400*500 elements @-)

Kf

jeremydouglass

@jaspervanblokland --

You are saying "a 2D array" but do you actually mean an object that contains a pair of variables -- like a PVector can be used to express an x and a y?

https://processing.org/reference/PVector.html

PVector mysize;
...
surface.setSize(mysize.x,mysize.y)

...and then you would want an array of PVectors (PVector[] mysizes) to contain multiple screen sizes...?

PVector[] mysizes;
...
surface.setSize(mysizes[i].x,mysizes[i].y)

jaspervanblokland

Yes, that is what i meant! Thank you!

Chrisir

PVector[] list = { 
  new PVector (111, 122), 
  new PVector (111, 142), 
  new PVector (154, 122)    
};



size (444, 777);

// use a for loop here 
ellipse (list[0].x, list[0].y, 5, 5);
ellipse (list[1].x, list[1].y, 5, 5);
ellipse (list[2].x, list[2].y, 5, 5);

// or write a funtion that gets a PVector and a diameter as parameters