There might not be a simple way. You might have to program your own way.
Imagine that you - not the computer - is trying to find repeated numbers in an array. What steps would you take to find them? What would you have to remember or keep track of while you're looking for them?
What you need to remember are the variables you need to use.
The steps you take become the code. Try writing it yourself!
// forum.Processing.org/two/discussion/16731/how-to-repeat-number-in-array
// GoToLoop (2016-May-21)
final int QTY = 10, RANGE = 10;
final byte[] vals = new byte[QTY];
for (int i = 0; i < QTY; vals[i++] = (byte) random(RANGE));
println(vals);
println();
IntDict count = new IntDict();
for (final byte num : vals) count.increment(str(num));
count.sortValuesReverse();
println(count);
for (final String k : count.keyArray()) if (count.get(k) < 2) count.remove(k);
println(count, ENTER);
count.sortKeys();
byte[] repeats = byte( int(count.keyArray()) );
println(repeats);
exit();
Answers
There might not be a simple way. You might have to program your own way.
Imagine that you - not the computer - is trying to find repeated numbers in an array. What steps would you take to find them? What would you have to remember or keep track of while you're looking for them?
What you need to remember are the variables you need to use.
The steps you take become the code. Try writing it yourself!
https://Processing.org/reference/IntDict.html