Processing 1.0 - Processing Discourse - Help with client / server Networking

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Index › Programming Questions & Help › Other Libraries › Help with client / server Networking

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Help with client / server Networking (Read 632 times)

deathbob

Help with client / server Networking
Nov 4^th, 2008, 11:03pm

When I try and get this code running on my school servers, it doesn't work, although it works fine here on my local computer. I have a server process running. Can I use 127.0.0.1 or do I need the real I.P. address the server is running on? (i assume it's the same local machine because the server is another processing applet in another folder in my home directory.)

Server Code after the Client code.

Quote:

import processing.net.*;
Client myClient;
int dataIn;
byte[] byteBuffer = new byte[10];

void setup(){
  frameRate(24);
  size(400,200);
  // myClient = new Client(this, "127.0.0.1", 10020);

  background(255);
  PFont myFont = loadFont("ArialRoundedMTBold-14.vlw");
  textFont(myFont);
  fill(0);
}

void draw(){
  try{
    text(myClient.ip(), 20, 130);
    if(myClient.available() > 0){
      String r = myClient.readString();
      text("Intercepted a Call from ",20,30);
      text(r, 20, 70);
    }
  }
  catch(Exception ex){
    fill(128);
    text("No Server", 30, 100);
  }
}

void mousePressed(){
  myClient = new Client(this, "127.0.0.1",10020);
}

deathbob

Re: Help with client / server Networking
Reply #1 - Nov 4^th, 2008, 11:03pm

I Guess I should post the server code too.

Quote:

import processing.net.*;
import SpringGUI.*;

Server myServer;
SpringGUI gui;

void setup(){
frameRate(30);
size(480,320);
background(255);
myServer = new Server(this, 10020);

PFont font = loadFont("TrebuchetMS-11.vlw");
textFont(font);
background(0,0,0);

gui = new SpringGUI(this);

gui.addTextField("myTextField","Enter Name and Number Here",10,40,180,20);
gui.setBackground("myTextField",0,0,0);
gui.setForeground("myTextField",255,255,255);

gui.addTextField("time","Enter Time Here",10,80,180,20);
gui.setBackground("time",0,0,0);
gui.setForeground("time",255,255,255);

gui.addList("myList",200,10,260,200);
gui.setAllBackgrounds(54,54,54);
gui.setAllForegrounds(255,255,255);

gui.addButton("myButton","Send",200,230,260,20);
gui.setBackground("myButton",0,0,0);
gui.setForeground("myButton",255,255,255);

}

void draw(){

// background(0,0,0,10);
fill(0,0,0,7);
rect(0,0,width,height);

}

void handleEvent(String[] parameters){
if(parameters[0].equals("TextField")&&parameters[2].equals("returnPressed")){
String CallerID = gui.getText("myTextField");
if(!CallerID.equals("")){
CallerID += " " + gui.getText("time");
myServer.write(CallerID);
gui.setText("myTextField","");
background(255,255,255);
gui.addItem("myList", CallerID);
}
}

if(parameters[1].equals("myButton")&&parameters[2].equals("mousePressed")){
String reSend = gui.getSelectedItem("myList");
myServer.write(reSend);
background(255,255,255);
}

if(parameters[0].equals("Button")&&parameters[2].equals("mouseEntered")){
gui.setBackground(parameters[1],164,0,0);
}
else if(parameters[0].equals("Button")&& parameters[2].equals("mouseExited")){
gui.setBackground(parameters[1],64,64,64);
}

if ( parameters[0].equals("TextField") && parameters[2].equals("mouseEntered") ) {
gui.setBackground(parameters[1], 0,128,164);
}
else if ( parameters[0].equals("TextField") && parameters[2].equals("mouseExited") ) {
gui.setBackground(parameters[1], 64,64,64);
}

}

dihardja Ex Member	Re: Help with client / server Networking Reply #2 - Nov 5^th, 2008, 11:28am maybe the server is blocked by a firewall on your school computer?

deathbob

Re: Help with client / server Networking
Reply #3 - Nov 21^st, 2008, 4:44pm

Hey, still trying to figure this out. Maybe I don't have the right mental model of what is going on. When I create the server with

myServer = new Server(this, 10020);

does "this" refer to the computer serving the webpage, or the computer the browser is running on?

Similarly for
myClient = new Client(this, "127.0.0.1",10020);
Should the client be listening to the port on the computer that the webserver is on, or the local host?

PhiLho

Re: Help with client / server Networking
Reply #4 - Nov 21^st, 2008, 5:33pm

deathbob wrote on Nov 21^st, 2008, 4:44pm:

myServer = new Server(this, 10020);

does "this" refer to the computer serving the webpage, or the computer the browser is running on

Neither, it refers to the running sketch (applet).

Quote:

Similarly for
myClient = new Client(this, "127.0.0.1",10020);
Should the client be listening to the port on the computer that the webserver is on, or the local host

It should be the same port anyway.

Did you tried to use the network IP address
I know that sometime you can have issues with localhost loopback, although I don't master these issues.

As dihardja points out, perhaps you should check if the school's computer has a firewall on, which might block this port (again, not sure if it works on localhost!).

deathbob

Re: Help with client / server Networking
Reply #5 - Nov 21^st, 2008, 5:44pm

Well that's what I'm trying to figure out. Where is the applet running? It seems like it's running in the browser, which makes me think the school firewall doesn't matter. If both applets are running on the users computer, in the users browser, why would it matter if the school server had a firewall?

If the applets are both running in the browser, they should work just like they do when i run them locally right? Unfortunately that is not what is happening. These programs run fine when i run them on my local computer, but do not work when I upload them to the school server and access them from there.

JohnG Ex Member	Re: Help with client / server Networking Reply #6 - Nov 21^st, 2008, 11:42pm I don't think the Java sandbox will let you run a server program in a browser and let anything connect to it. You'd have to run the server standalone from processing itself.

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