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Topic: Ringpolygon (Read 410 times) |
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eskimoblood
 
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Ringpolygon
« on: Feb 13th, 2005, 3:51pm » |
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Is there a way to draw ringpolygons in processing?
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fry
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Re: Ringpolygon
« Reply #1 on: Feb 13th, 2005, 8:07pm » |
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what's a ringpolygon?
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JohnG
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Re: Ringpolygon
« Reply #2 on: Feb 14th, 2005, 12:46pm » |
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If you mean is there a way to draw rings, then there's no built in way, but the following code shoudl do what you want, I think:
Code:
void ringpoly(float radius, float _size, int segments)
{
float dt=TWO_PI/(float)segments;
//dt = delta theta, i.e. how wide is each segment, in radians.
for(int i=0;i<segments;i++)
{
beginShape(QUADS);
{
//work clockwise around segment, so it looks correct
vertex(radius*sin(dt*i),radius*cos(dt*i),0);
vertex(radius*sin(dt*(i+1)),radius*cos(dt*(i+1)),0);
vertex((radius+_size)*sin(dt*(i+1)),(radius+_size)*cos(dt*(i+1)),0);
vertex((radius+_size)*sin(dt*i),(radius+_size)*cos(dt*i),0);
}
endShape();
}
}
void setup()
{
size(400,400);
background(0);
translate(width/2,height/2);
ringpoly(150,25,32);
fill(255,0,0);
ringpoly(100,25,16);
fill(0,255,0);
ringpoly(50,25,4);
}
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eskimoblood
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Re: Ringpolygon
« Reply #3 on: Feb 14th, 2005, 4:53pm » |
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on Feb 13th, 2005, 8:07pm, fry wrote:
its a polygon with a hole
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