Turning on relays via serial port,building the GUI

Answers

• Lord_of_the_Galaxy

  October 2016 edited October 2016 Answer ✓

  Fairly simple actually, all you have to do is add an else statement after your if statement, and inside it draw an ellipse with the other color.
  BTW, your first program may not work properly when pressing more than one key at a time, though I could be wrong.
• kfrajer

  October 2016 Answer ✓

  One way to do things....

  Kf

  P.S. I am not fan of managing keyPressed in draw. I have seen some unwanted behavior before.

  final color buttonON = color(0, 255, 0);  //Green
  final color buttonOFF = color(0, 0, 0);    //Black
  
  color button1;
  int posB1x=20;
  int posB1y=20;
  
  void setup() {
    size(400, 400);
    ellipse(20, 20, 20, 20);
  }
  void draw() {
  
    fill(button1);
    ellipse(posB1x,posB1y, 20, 20);
  } 
  
  void keyPressed() {
    if (key == '1') 
      button1=buttonON;
  }
  
  void keyReleased() {
    if (key == '1') 
      button1=buttonOFF;
  }
  
• Lord_of_the_Galaxy

  November 2016

  @kfrajer it is a good example.
  More complex version, here you just need the ASCII code of a character to know if it is pressed on the keyBoard(will add support for special, i.e. coded, characters later):

  boolean[] pressed = new boolean[256];
  
  void setup(){
    size(400, 400);
    //REQUIRED
    for(int i = 0; i < pressed.length; i++){
      pressed[i] = false;//required to prevent NullPointerAccess
    }
    //NOT REQUIRED - just an example
    noStroke();
    fill(255);
    textSize(25);
  }
  
  void draw(){
    //NOT REQUIRED - just an example
    for(int x = 0; x < 16; x++){
      for(int y = 0; y < 16; y++){
        //not very wise of me to do it in a hardcoded way
        if(pressed[x + y*16]){
          fill(0);
          rect(x*25, y*25, 25, 25);
          fill(255);
          text((char)(x + y*16), x*25, (y+1)*25);
        }else{
          rect(x*25, y*25, 25, 25);
        }
      }
    }
    //READ ME
    //To find whether a key is pressed - pressed[key] will store whether it is pressed, where key is the ASCII code of the letter
    //Example - pressed['1'] will be true only when the no 1 key is pressed
  }
  
  //NOTE: Even this fails if two keys are pressed(or released) at the exact same time
  //NOTE 2: It also does not work(I don't know why) when I press more than 5 buttons at a time 
  void keyPressed(){
    if(key < 256)pressed[key] = true;//ignore most non-ASCII characters
  }
  
  void keyReleased(){
    if(key < 256)pressed[key] = false;//ignore most non-ASCII characters
  }