Limiting floating numbers to 2 decimal places

Answers

• koogs

  August 2017

  nf()
• jeffmarc

  August 2017

  Thanks, but nf() requires a left and right value. I want the right to always be 2 significant digits but could live with the 0 fill for example 23.40 instead of 23.4 but the left number of significant digits changes. If i use 6, it pads 0's in front . example 23.40 becomes 000023.40

  I don't want the leading 0's in the numbers but want to maintain room for a maximum of 6 significant digits.

  In C there is print format statement like 6.2lf for floating point numbers.

  Any equivalent in Processing? or maybe a function to call with number, format info and location.
• GoToLoop

  August 2017 Answer ✓

  http://Docs.Oracle.com/javase/8/docs/api/java/util/Formatter.html
• jeffmarc

  August 2017 Answer ✓

  Made a function to do it. It works convert to string then use str.indexOf(.) to get number of sig digits to left then nf(strval,strval.indexOf("."),2) to return modified string version of number for text.
• koogs

  August 2017 Answer ✓

  how is this not what you want?

  float f1 = 1.2;
  println(nf(f1, 0, 2)); // 1.20
  
  float f2 = 1.234;
  println(nf(f2, 0, 2)); // 1.23
  
  float f3 = 1.0;
  println(nf(f3, 0, 2)); // 1.00
  
  float f4 = 1234.567;
  println(nf(f4, 0, 2)); // 1234.57 - rounded up
  
• jeffmarc

  August 2017

  Duh. I didn't realize 0 was an acceptable parameter for the left parameter in nf() Thanks