problem with maths

Gargulio

float a=1/10;
print (a);                  // 0.0
float b=1*0.1;
print (b);                  //0.1

calsign

Please see Why does 2 / 5 = 0 instead of 0.4?

Gargulio

thank you so much !!!

GoToLoop

final float a = 1/1e1;
println(a);

final float b = 1/10.0;
println(b);

final float c = (float) 1/10;
println(c);

exit();

mradul_modi

The reason for 1 being displayed as the result is that compiler treats the division result to be an integer. The numerator and denominator in the expression are both integers hence the result. This can be avoided by explicitly type casting the data as float type.

quark

@GoToLoop - not sure why you have made these constants :-/ but anyway here are three more for your collection.

float d = 1/10f;
println(d);

float e = 1f/10;
println(e);

float f = 1/(float)10;
println(f);