Is it possible to make my random string appear all but only one time each, during the run ?

alicessing

I have random texte that appears but I would like each sentence (string) to appear only one time each, during the running of the sketch. Also to go to the line I use \n is there any way to constrain my string to do it alone ? Thanks you very much !

kfrajer

Can you post the code you have so far? It will be useful to see your approach.

Do you have your strings stored in an array?

This next post does not answer your question but it shows one possible idea: https://forum.processing.org/two/discussion/comment/90020/#Comment_90020

Kf

jeremydouglass

@alicessing --

If you put your strings in a StringList then you can use remove to take out each randomly chosen string after it is used.

• https://processing.org/reference/StringList.html
• https://processing.org/reference/StringList_remove_.html

alicessing

Thanks ! I am going to look at your suggestion. I have something like 100 sentences I don't think I can do it by using String list or I will have to create an inventory.append("") for each of my sentences ? Here is my code :

import processing.pdf.*;

PFont typo;
PImage paper;
String titre = "Manifeste"; 


String [] phrase1 = { 
"Tranchons-en : le merveilleux est toujours beau, \nn'importe quel merveilleux est beau, il n'y a même que le merveilleux qui soit beau.","Aucun critère technologique n'est nécessaire, si ce n'est que l'oeuvre doit exister sur un ou plusieurs ordinateurs.","L’homme doit garder ses racines, savoir d’où il est.","Il faudrait redonner un sens à la vie communautaire.","Il y a un travail urgent à fournir : recueillir les fauves ou récits de veillée, les chansons populaires, les coutumes…","Le passé doit seulement constituer un enseignement."
};

float x, y;


void setup() {
  size(827, 1170, PDF, "manifeste.pdf");
 // size(2480,3508); 850 500
  smooth();
  frameRate(1);
  background(255);
  fill(50);     //! 
//typo = createFont("Cambria", 10);
  typo = createFont("Cambria-48", 10);  
  textFont(typo, 12);
 // textFont(typo, 15);
 // text(titre,10,50);
 }

void draw() {


  background(255);

  y = y + 110;
 text(phrase1[int(random(0, phrase1.length))], 50, 50);
 text(phrase1[int(random(0, phrase1.length))], 50, 150);
 text(phrase1[int(random(0, phrase1.length))], 50, 250);
 text(phrase1[int(random(0, phrase1.length))], 50, 350);
 text(phrase1[int(random(0, phrase1.length))], 50, 450);
 text(phrase1[int(random(0, phrase1.length))], 50, 550);
 text(phrase1[int(random(0, phrase1.length))], 50, 650);
 text(phrase1[int(random(0, phrase1.length))], 50, 750);
 text(phrase1[int(random(0, phrase1.length))], 50, 850);
 text(phrase1[int(random(0, phrase1.length))], 50, 950);
 text(phrase1[int(random(0, phrase1.length))], 50, 1050);


PGraphicsPDF pdf = (PGraphicsPDF) g;  
 pdf.nextPage();  

 if (frameCount ==5) {   
   exit();    

}

Chrisir

instead of \n look at text () with 5 parameters which is text in a box so to speak

You could shuffle the list and then bring in a counter that just goes through it with a simple ++

jeremydouglass

@alicessing --

Edit: You can create a new StringList directly from a String[] array (see GoToLoops answer below).

String[] phrase1 = {"a","b","c","d"};
StringList phraselist = new StringList(phrase1);

You can also load strings from an array into an existing StringList with an enhanced for loop:

• https://processing.org/reference/for.html

...taking the form:

for (datatype element : array) { 
  statements
}

Like this:

// load string array into existing StringList
StringList phraselist = new StringList();
// ....
String[] phrase1 = {"a","b","c","d"};
for (String element : phrase1) {
  phraselist.append(element);
}

Once you have a StringList it can be shuffled using its shuffle() method:

• https://processing.org/reference/StringList_shuffle_.html

...like this:

// shuffle
phraselist.shuffle();
println(phraselist);

Output:

StringList size=4 [ "c", "d", "b", "a" ]

For very long lists of strings, consider saving them in a text file and loading them using loadStrings:

• https://processing.org/reference/loadStrings_.html

...like this:

String[] phrase1 = loadStrings("phrase1.txt");

koogs

your big problem is drawing everything in the same iteration of draw().

the screen is only updated at the end of each call to draw().

https://forum.processing.org/two/discussion/8085/i-display-images-in-sequence-but-i-see-only-the-last-one-why

GoToLoop

// forum.Processing.org/two/discussion/21425/
// is-it-possible-to-make-my-random-string-appear-all-
// but-only-one-time-each-during-the-run#Item_7

// 2017-Mar-16

final String[] phraseArray = {
  "Il n'y a même que le merveilleux qui soit beau", 
  "Aucun critère technologique n'est nécessaire,", 
  "Si ce n'est que l'œuvre doit exister sur un ou plusieurs ordinateurs.", 
  "L'homme doit garder ses racines,", 
  "Il faudrait redonner un sens à la vie communautaire."
};

printArray(phraseArray);
println();

final StringList phraseList = new StringList(phraseArray);
phraseList.shuffle();
println(phraseList, ENTER);

phraseList.array(phraseArray);
printArray(phraseArray);

exit();

kfrajer

There is also the split and splitTokens functions. If you write your phrases and they are separated by a special character (for example... your phrases enclosed in quote remarks) then you can use split like this:

String modified_phrase1="\"phrase1\"\"phrase2\"";
println("ORIGINAL PHRASES: "+modified_phrase1);

String[] phrases = split(modified_phrase1, "\"");
println("PHRASES FOUND USING SPLIT"+phrases.length);
for(int i=0;i<phrases.length;i++)
println(i+" "+phrases[i]);


String[] phrases2 = splitTokens(modified_phrase1, "\"");
println("PHRASES FOUND USING SPLITTOKEN"+phrases2.length);
for(int i=0;i<phrases2.length;i++)
println(i+" "+phrases2[i]);

The main difference is that split will produce empty Strings between contiguous delimiters while splitTokens doesn't. It treats contiguous delimiters together

Kf

alicessing

Thanks very much everybody and thanks for your explanations this is not exactly what I wanted to do but finaly I think it is a better thing like this and it going to be easier for me for what I want to do then. And I will keep to try to do the other things by myself :)

Chrisir

import processing.pdf.*;

PFont typo;
PImage paper;
String titre = "Manifeste"; 


String [] phrase1 = { 
  "Tranchons-en : le merveilleux est toujours beau, \nn'importe quel merveilleux est beau, il n'y a même que le merveilleux qui soit beau.", 
  "Aucun critère technologique n'est nécessaire, si ce n'est que l'oeuvre doit exister sur un ou plusieurs ordinateurs.", 
  "L’homme doit garder ses racines, savoir d’où il est.", "Il faudrait redonner un sens à la vie communautaire.", 
  "Il y a un travail urgent à fournir : recueillir les fauves ou récits de veillée, les chansons populaires, les coutumes…", 
  "Le passé doit seulement constituer un enseignement."
};

float x, y=33;

int phraseCounter;

PGraphicsPDF   pdf = (PGraphicsPDF) g;

void setup() {

  // size(827, 1170, PDF, "manifeste.pdf");
  // size(2480,3508); 850 500
  size(1280, 908); // size(2480,3508); 850 500 

  smooth();
  frameRate(1);
  background(255);



  fill(50);     //! 
  //typo = createFont("Cambria", 10);
  typo = createFont("Cambria-48", 10);  
  textFont(typo, 12);
  // textFont(typo, 15);
  // text(titre,10,50);


  // we shuffle phrase1 !!!!!!!!!!
  final StringList phraseList = new StringList(phrase1);
  phraseList.shuffle();
  // println(phraseList, ENTER);

  //phrase1
  phraseList.array(phrase1);
  printArray(phrase1);

  println ("Press any key to go to next page");
}

void draw() {

  background(255);

  text(phrase1[phraseCounter], 
    50, y, 
    120, 700);

  //pdf.nextPage();  

  //if (frameCount ==5) {   
  //  exit();
  //}
  //
}

void keyPressed() {

  if (phraseCounter>=phrase1.length-1)
    return; // leave here  

  phraseCounter++;
  y = y + 110;

  //  pdf.nextPage();
}
//