Negative mods aren't handled well

vpersaud03

example: -1 mod 4 should return 3

quark

-1 mod 4 should return -1

because the standard order of precedence means that the unary minus is performed before the modulus.

I have edited the above statement because the original was a mistake and didn't match the first line. Sorry about that, I should read my posts more carefully.

GoToLoop

Hmmm... That's not what I see! b-(

println((-1) % 4);

AFAIK, all unary operators have higher precedence than any other binary operators.
Both for programming & mathematics!!! ~:>

Modulo binary operator % should never happen before negative unary operator -!!! 8-X

koogs

i always (n + m) % m (which only works if n is never going below -m, which it isn't, usually)

(((n % m) + m) % m) should work. longwinded though.

GoToLoop

Excellent @koogs! o=>

final int n = -1, m = 4;

println(n % m);             // -1
println((n + m) % m);       // 3
println((n % m  + m) % m);  // 3

exit();

quark

@koogs of course - looking for wrap around values - well spotted