I had problems while trying to show the result of my HashMap in a String. When I Iterate through the HashMap, I get the name of the elements in it and an Integer containing the number of times it appears. My problem appears when I try to get my results in a String to show it to the user. If I fill the String with the current element, I get only the last one. If I type "myString = myString + currentElement + "\n";", the results are up to date every time but the keep going under each other because of the "\n". I want myString to be placed somewhere in the screen so that everytime I add the same element in my HashMap it keeps the count up to date.

Here's the code :
Code:

HashMap words = new HashMap();
String restant = "",name;

void setup() {
  size(500,500);
} 

void draw() {
  background(0);
  stroke(255);
  line(width/2,0,width/2,height);
  line(0,height/2,width,height/2);
  try {
  text(words.get("rightUp").toString(), width/2+10,10);
  text(words.get("rightDown").toString(), width/2+10,height/2+10);
  text(words.get("leftUp").toString(), 10,10);
  text(words.get("leftDown").toString(), 10,height/2+10);
  text(restant,5,height/2-40);
  } catch (NullPointerException e) {}
}

void mouseReleased() {
  if (mouseX > 0 && mouseX < width/2 && mouseY > 0 && mouseY < height/2) {
    addWord("leftUp");
  }
  else if (mouseX > width/2 && mouseX < width && mouseY > 0 && mouseY < height/2) {
    addWord("rightUp");
  }
  else if (mouseX > width/2 && mouseX < width && mouseY > height/2 && mouseY < height) {
    addWord("rightDown");
  }
  else if (mouseX > 0 && mouseX < width/2 && mouseY > height/2 && mouseY < height) {
    addWord("leftDown");
  }
  else if (mouseX == width/2) {
    addWord("COQUITLAM");
  }
  else if (mouseY == height/2) {
    addWord("MEDICINE HAT");
  }
  printWords();
}

void addWord(String value) {
  Integer n = (Integer)words.get(value);
  int count = (n!=null ? n.intValue()+1 : 1);
  words.put(value,new Integer(count));
}

void printWords() {
  Iterator iter = words.keySet().iterator();
  while(iter.hasNext()){ 
    name = iter.next().toString();
    if (name.equals("rightUp") == false && name.equals("leftUp") == false && name.equals("rightDown") == false && name.equals("leftDown") == false) {
	println(name + " " + words.get(name));
	if (keyPressed) {
	restant = restant + "\n" + name + " " + words.get(name);
	}
    }
  }
} 

I'm not sure I understood your question, but here are some comments on your code - I hope this helps

In the draw method, instead of catching the NullPointerException and ignoring it, you should check if the value is null. Once the exception is thrown the following lines of code are not executed, which may lead to unexpected results.

Instead of
Code:

try {
  text(words.get("rightUp").toString(), width/2+10,10);
  text(words.get("rightDown").toString(), width/2+10,height/2+10);
  text(words.get("leftUp").toString(), 10,10);
  text(words.get("leftDown").toString(), 10,height/2+10);
  text(restant,5,height/2-40);
  } catch (NullPointerException e) {} 

I would use a helper function to test if the value is null
Code:

  text(getNum("rightUp"), width/2+10,10);
  text(getNum("rightDown"), width/2+10,height/2+10);
  text(getNum("leftUp"), 10,10);
  text(getNum("leftDown"), 10,height/2+10);
  text(restant,5,height/2-40);
 

Code:

String getNum(String w) {
  Integer n = (Integer)words.get(w);
  if (n == null)
    return "0";
   return n.toString(); 
}
 

The second thing is that you should probably initialize the String you are using for the results at the beginning of the  printWords method to an empty String. It should look something like this:
Code:

void printWords() {
  restant = "";
  Iterator iter = words.keySet().iterator();
  while(iter.hasNext()){ 
    name = iter.next().toString();
    if (name.equals("rightUp") == false && name.equals("leftUp") == false && name.equals("rightDown") == false && name.equals("leftDown") == false) {
	println(name + " " + words.get(name));
    }	
    restant = restant + name + " " + words.get(name) + " ";
 }
 

Hope this helps  

I never tought that it could be a solution to empty the string each time I add a value! XD   Thanks alot for that!

Also, do you know why there are functions imported from pure java and supported by Processing that aren't colored in orange like the other keywords?

Ok so there is a list of words that fry and REAS choosed to be the most common used that are colored. When I started learning Processing my teacher used those keywords that wern't colored and I was always mystified!

Thanks for your time PhiLho and again, thanks guyy for those precious tips!