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Index › Programming Questions & Help › Syntax Questions › loop case in switch
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loop case in switch (Read 1226 times)
barelief
loop case in switch
May 25th, 2010, 2:25pm  
hello,
i want num keys to trigger events.
is it possible to loop case somehow?

here's the idea:

Quote:
switch (key)
{
 for (int i=1;i<10;i++){
 case  i:
   println("you pressed "+i);
   break;
 }
}
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koogy
Re: loop case in switch
Reply #1 - May 25th, 2010, 2:58pm  
no, the 'arguments' to case statements must be known at compile time.

but there's no need for the case or loop:

  println("you pressed "+ key);

probably should put a check in there to make sure that it's a digit.

if you want the number associated with the key (key is a single character, not a number) then take '0' away from it.

int ch = key - '0';
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barelief
Re: loop case in switch
Reply #2 - May 25th, 2010, 4:06pm  
here's my original code, and i was looking for solution to avoid copypasting:

Code:

 switch (key) {

  case '1':
    piano[0].x=mouseX; 
    piano[0].w=piano[0].x*2;
    break;
  case '2':
    piano[1].x=mouseX; 
    piano[1].w=(piano[1].x-(piano[0].x+piano[0].w/2))*2; 
    break;
  case '3':
    piano[2].x=mouseX; 
    piano[2].w=(piano[2].x-(piano[1].x+piano[1].w/2))*2;
    break;
  case '4':
    piano[3].x=mouseX; 
    piano[3].w=(piano[3].x-(piano[2].x+piano[2].w/2))*2;
    break;
  case '5':
    piano[4].x=mouseX; 
    piano[4].w=(piano[4].x-(piano[3].x+piano[3].w/2))*2;
    break;
  case '6':
    piano[5].x=mouseX; 
    piano[5].w=(piano[5].x-(piano[4].x+piano[4].w/2))*2;
    break;
  case '7':
    piano[6].x=mouseX; 
    piano[6].w=(piano[6].x-(piano[5].x+piano[5].w/2))*2;
    break;
  case '8':
    piano[7].x=mouseX; 
    piano[7].w=(piano[7].x-(piano[6].x+piano[6].w/2))*2;
    break;
}


anyway thanks:)
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PhiLho 
Re: loop case in switch
Reply #3 - May 25th, 2010, 10:20pm  
Code:
int idx = key - '1';
piano[idx].x = mouseX; 
int prev = 0;
if (idx > 0) 
{
  prev = piano[idx-1].x + piano[idx-1].w/2;
}
piano[idx].w = (piano[idx].x - prev) * 2;

(untested)
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