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Index › Programming Questions & Help › Syntax Questions › print when same angle
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print when same angle (Read 890 times)
jirko
print when same angle
May 9th, 2010, 9:44am  
Hi,
I have a problem I can't solve.
I need two know when two shapes has the same angle. I have made a small sketch to illustrate the issue:

Code:
float centerAngleO;
float centerAngleT;

float posXcenterLine;
float posYcenterLine;
float posXoutLine;
float posYoutLine;

void setup() {
  size(400,400);
  frameRate(15);
  }

void draw() {
  
  background(255);
  translate(width/2,height/2);
  centerAngleO += PI/240;
  rotate(-centerAngleO);
  lineO();
  
  centerAngleT += PI/60;
  rotate(-centerAngleT);
  lineT();
  
  check();
}

void lineO(){
  for(int i=0; i<32; i++){
    posXcenterLine=i+40;
    posYcenterLine=i+40;
    strokeWeight(10);
    line(posXcenterLine,posYcenterLine,10,10);}
}

void lineT(){
  for(int i=0; i<32; i++){
    posXoutLine=i+80;
    posYoutLine=i+80;
    strokeWeight(10);
    line(posXoutLine,posYoutLine,120,120);}
}
  
void check(){
  if(posXcenterLine==posXoutLine){
    print("yepa");}
} 
  


any help will be much appreciated!
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« Last Edit: May 9th, 2010, 10:46am by N/A »  
 
amnonP5
Re: print when same angle
Reply #1 - May 9th, 2010, 1:04pm  
How about this?

Code:
int yeswecan;
int angle1,angle2;

void setup() {
  size(400,400);
  smooth();
  frameRate(15);
}

void draw() {
  background(255);
  translate(width/2,height/2);

  angle1 += 1;
  angle2 += 10;

  rotate(-radians(angle1));
  strokeWeight(5);
  stroke(200,0,0);
  line(0,0,75,0);
  rotate(radians(angle1));

  rotate(-radians(angle2));
  strokeWeight(2);
  stroke(0);
  line(75,0,150,0);
  rotate(radians(angle2));

  check();

}

void check(){
  if (angle1 >= 360) {angle1 = 0;}
  if (angle2 >= 360) {angle2 = 0;}

  if(angle1 == angle2){
    fill(200,0,0);
    ellipse(0,0,25,25);
    yeswecan++;
    println("YES WE CAN! (" + yeswecan + ")");
    // proof it's accurate even after 5 or 500 spins :)
    if (yeswecan == 5) {noLoop();}
  }
}
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jirko
Re: print when same angle
Reply #2 - May 10th, 2010, 2:29am  
Hi amnonP5,

nice and very simple solution. Seems to work very accurate!
Smiley

Thanks a lot!!!
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