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Index › Programming Questions & Help › Other Libraries › ControlP5 two listboxes
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ControlP5 two listboxes (Read 1203 times)
convex
ControlP5 two listboxes
Apr 13th, 2010, 12:41pm  
Hi, I am new to Processing and I really like it!

I am playing with the examples from Fry's book and trying some libraries too.  I need some help here.  I am trying ControlP5 and added two listboxes.  I found that I could not distinguish events from the two listboxes.  I used the piece of codes from ControlP5 example
  if (theEvent.isGroup()) ...
but of course this does not distinguish between the two listboxes.

I added group ids to the boxes but it was not working.

Any tip is appreciated!

Thanks,
max
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sojamo
Re: ControlP5 two listboxes
Reply #1 - Apr 14th, 2010, 4:35am  
the following works for me:
create 2 listBoxes (in setup)
Code:

  ListBox l1 = controlP5.addListBox("myList1",100,100,120,120);
  l1.setId(1);
  ListBox l2 = controlP5.addListBox("myList2",240,100,120,120);
  l2.setId(2);
  for(int i=0;i<80;i++) {
    l1.addItem("item "+i,i);
    l2.addItem("item "+i,i);
  }

check the id of a listBox inside controlEvent()
Code:

void controlEvent(ControlEvent theEvent) {
  if (theEvent.isGroup()) {
    println(theEvent.group().id());
  }
}

prints 1 for the first listBox and 2 for the second.
does that work for you?
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andreas schlegel / http://www.sojamo.de
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convex
Re: ControlP5 two listboxes
Reply #2 - Apr 16th, 2010, 3:26am  
Thanks a lot, sojamo!

I actually tried using id but I must have made some mistakes so it didn't work, but your solution does!!
(and you can see that I am not a programmer...)

BTW, thanks for the ControlP5 library!  REALLY love it!!
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