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Index › Programming Questions & Help › Programs › Noob can't get println to do anything
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Noob can't get println to do anything (Read 758 times)
lala
Noob can't get println to do anything
Apr 13th, 2010, 5:53am  
Hiya.  I'm just getting started with Processing and I'm trying to do a simple:

println("Hello World!\n");

All I get is a grey square with this.  I also tried copy pasting the println example from the reference pages and I get the same result.  This problem doesn't seem to be in the faq and I can't find anyone else talking about this problem on the forums, so I can only conclude that I'm being a complete moron.  Could anyone explain what I'm doing wrong?
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PhiLho 
Re: Noob can't get println to do anything
Reply #1 - Apr 13th, 2010, 6:22am  
First note: \n is a bit redundant with the "ln" part of the function, unless you want to skip two lines.
Second note: you should indicate which version of Processing you have downloaded, and on which system you use it.
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Lie Ryan
Re: Noob can't get println to do anything
Reply #2 - Apr 13th, 2010, 6:40am  
The output of println() shows up in the blackbox below the text editor, not in the drawing window. Are you sure you're expecting for it at the right place?
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PhiLho 
Re: Noob can't get println to do anything
Reply #3 - Apr 13th, 2010, 6:45am  
Good remark Lie Ryan!
The "grey square" is probably the default sketch area (I thought about "unknown font" symptom instead).

Yes, println is to dump debug information on the console, below the text editor, in a persistent way (ie. you can scroll back, etc. but you loose that when restarting the sketch).
To show text on the sketch area, use the text() function (and load font first).
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lala
Re: Noob can't get println to do anything
Reply #4 - Apr 13th, 2010, 7:31am  
Doh!  I was indeed looking for it in the wrong place.  Thank you very much.
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