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Index › Programming Questions & Help › Programs › Hit Testing A Diagonal Line.
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Hit Testing A Diagonal Line. (Read 687 times)
Nnd.
Hit Testing A Diagonal Line.
Apr 8th, 2010, 4:59pm  
Hi all.

How would I go about hit testing a diagonal line?

For example, I have a vertical line, and am checking for a particular range of X values, followed by a range of Y values, contained within four 'if' statements (see code below). This works fine.

if(x1 >= 100){
       if(x1 <= 200){
         if(y1 >= 100){
           if(y1 <= 200){
             p1 = true;
           }
         }
       }
     }

However, on a diagonal line, the X condition changes depending on the Y value. Is there a way to construct this structure above to change the X value depending on the Y value? Or perhaps a completely different method?

Many thanks.
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Cedric
Re: Hit Testing A Diagonal Line.
Reply #1 - Apr 8th, 2010, 5:08pm  
i am not sure if i get you right but Casey has some nice intersection examples online http://www.openprocessing.org/portal/?userID=54
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... twitter.com/CedricKiefer
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yconst
Re: Hit Testing A Diagonal Line.
Reply #2 - Apr 8th, 2010, 5:11pm  
You're into line-(something) intersection. So you should define what your other shape is. Search for e.g. line-circle intersection. There are plenty of processing libs that do that I guess.
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Yiannis Chatzikonstantinou
volatile prototypes
 
Nnd.
Re: Hit Testing A Diagonal Line.
Reply #3 - Apr 8th, 2010, 5:12pm  
Brilliant, thanks a lot.

Yes, he seems to be demonstrating exactly what I was after.

Thanks again.
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yconst
Re: Hit Testing A Diagonal Line.
Reply #4 - Apr 8th, 2010, 5:12pm  
heh cedric u got me there Tongue
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Yiannis Chatzikonstantinou
volatile prototypes
 
Cedric
Re: Hit Testing A Diagonal Line.
Reply #5 - Apr 8th, 2010, 5:20pm  
Smiley

if shapes are getting more complex, http://www.ricardmarxer.com/geomerative/ is another way to go.
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... twitter.com/CedricKiefer
WWW CedricKiefer 9570393 CedricKiefer  
Nnd.
Re: Hit Testing A Diagonal Line.
Reply #6 - Apr 8th, 2010, 5:25pm  
That's excellent. Thanks for your quick help.
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