We closed this forum 18 June 2010. It has served us well since 2005 as the ALPHA forum did before it from 2002 to 2005. New discussions are ongoing at the new URL http://forum.processing.org. You'll need to sign up and get a new user account. We're sorry about that inconvenience, but we think it's better in the long run. The content on this forum will remain online.

Index › Programming Questions & Help › Syntax Questions › 1.4901161E-8 as output etc

clankill3r Full Member Offline Posts: 210 Netherlands	1.4901161E-8 as output etc? Mar 17th, 2010, 2:55pm   I get things like 1.4901161E-8 in the output, is that correct or is there something wrong with my syntax? Code: float yShift = 0; float step = 0.1; float dir = 1; for(int i = 0; i < 400; i++){ yShift += step*dir; if(yShift > 1 || yShift < 0.0){ dir = -dir;; } println(yShift); }

Cedric YaBB Moderator Offline Posts: 1838	Re: 1.4901161E-8 as output etc? Reply #1 - Mar 17th, 2010, 3:17pm   nope, everything is fine. never typed some really large numbers on your calculator in school?
	twitter.com/CedricKiefer

Smitty Junior Member Offline Posts: 97

Re: 1.4901161E-8 as output etc? Reply #2 - Mar 17th, 2010, 6:02pm   clankill3r wrote on Mar 17th, 2010, 2:55pm: I get things like 1.4901161E-8 in the output, is that correct or is there something wrong with my syntax 1.4901161E-8 is: 1.4901161 * 10^(-8), which is: 0.000000014901161 It's normal.  Floating point numbers get rounded from time to time in odd places, so if you do a long string of operations that should add up to zero, sometimes it won't come out to exactly zero.

clankill3r Full Member Offline Posts: 210 Netherlands	Re: 1.4901161E-8 as output etc? Reply #3 - Mar 18th, 2010, 1:09am   in school all i got on my calculator was a E in the end and i thought that was for error. thx