I'm working with a set of strings that represent numerical values from 1-22. These values were loaded from a text file. I want to convert the strings into ints so that I can perform some logic so, I wrote the following method. However, the conversion does not happen. Any idea?
Many Thanks!

Code:

int stringToPosInt(String number){
  int j=0;
  for(int i=0; i < 23; i++){
    String temp = Integer.toString(i);
    println(number+temp+"*");
    if(number.equals(temp)){
	j = i; 
    }
  }
  return j;
} 

Perhaps some more info could help. The strings I've loaded are stored in an array of ArrayLists. I have no problem referencing each stored string, as long as I am performing some string operation. .e.g. println() or text(). Before calling the method I posted earlier, I cast the object, returned from the ArrayList as a String in a for loop index by ints i and j:


String num = (String)arrayN[i].get(j)

Could there be some issue in converting an object cast as String in the method I'm proposing from above?

Hello,

yes, I think andrew.madison is right, there is an issue - or I ran into the same trap as he?  

When I try

println ('A');
println (int('A'));

I get A and 65.

With
println (int('1'));
println (int("1"));
I get
49 and 1.

So the trouble might be that
an int from a char returns the
ascii and not the number.

I assume andrew.madison ran into this....

To avoid this I prepared a little function until someone shows me the light...  

Greetings, Chrisir  



int CharFromArray(String MyTestArray, int i){

 return(MyTestArray.charAt(i));

} // int

int IntegerFromArray(String MyTestArray, int i){

 int Buffer = 0;

 switch (MyTestArray.charAt(i)) {
 case '0':
   Buffer = 0;
   break;

 case '1':
   Buffer = 1;
   break;

 case '2':
   Buffer = 2;
   break;

 case '3':
   Buffer = 3;
   break;  

 case '4':
   Buffer = 4;
   break;  

 case '5':
   Buffer = 5;
   break;  

 case '6':
   Buffer = 6;
   break;  

 case '7':
   Buffer = 7;
   break;  

 case '8':
   Buffer = 8;
   break;  

 case '9':
   Buffer = 9;
   break;  

 default:
   //
   break;

 } // switch

 return ( Buffer ) ;

}

You could also use:

int IntegerFromArray(String MyTestArray, int i){

 return (MyTestArray.charAt(i) - '0');

}

Although, this does not catch non-numeric characters.

Chrisir wrote on Mar 6^th, 2010, 3:26am:

No, the problems are different. He wanted to convert a string holding numbers to int. You want to convert a char holding a digit to int. String is made of chars, but they are different beasts.
NoahBuddy's solution is OK but addresses a different need (sticking to original goal of String parameter).
In your case, it would be just:
Code:

int integerFromChar(char myChar) {
  return myChar - '0';
}
// or, for a more robust function:
int integerFromChar(char myChar) {
  if (myChar < '0' || myChar > '9') return -1;
  return myChar - '0';
}