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User functions? (Read 379 times)
Fil
User functions?
Jun 9th, 2009, 12:32pm  
So, I just started a program and I created a helper function:

Code:
private void findSlopeIntercept {
  this.m = (y[2]-y[1])/x[2]-x[1]);
  this.b = y[1]-(m*x[1]);
}


When I try to give it a test run, I get an error at private. So now I'm not even sure if user created functions are legal in Processing.

I think I could outsource everything to an outside class, or failing that I could write everything out directly. But both ways seem kind of messy.

I'm new to Processing, and I haven't found anything on this. I figured the boards would be the quickest way to get an answer.
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Scott Murray
Re: User functions?
Reply #1 - Jun 9th, 2009, 12:51pm  
Don't forget to add the parens after your function name:

private void findSlopeIntercept() {
 this.m = (y[2]-y[1])/x[2]-x[1]);
 this.b = y[1]-(m*x[1]);
}
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Fil
Re: User functions?
Reply #2 - Jun 9th, 2009, 12:59pm  
That was my slip.

I also had to remove private from the function. I guess Processing doesn't accept that.
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Scott Murray
Re: User functions?
Reply #3 - Jun 9th, 2009, 1:02pm  
What happens when you get rid of "private"?  I've only ever seen private functions used within classes, never just in the main sketch.  (Not sure it will work.)
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Fil
Re: User functions?
Reply #4 - Jun 9th, 2009, 1:07pm  
Scott Murray wrote on Jun 9th, 2009, 1:02pm:
What happens when you get rid of "private"  I've only ever seen private functions used within classes, never just in the main sketch.  (Not sure it will work.)


Sorry, I edited my post as you responded.

It works now as:

Code:
void findSlopeIntercept() {
  m = (y[2]-y[1])/(x[2]-x[1]);
  b = y[1]-(m*x[1]);
}


I'm a bit wary with using all global variables, but it doesn't seem to work otherwise. I don't know if its Processing or if I'm just rusty with my Java.

There isn't really a need for private in this case anyways, it's just a habit of mine.
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