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Index › Programming Questions & Help › Syntax Questions › How do you make increments greater than 1
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How do you make increments greater than 1 (Read 185 times)
torifoster
How do you make increments greater than 1
Nov 25th, 2008, 10:55pm  
I would like to make a variable increase by 15 each time. How do I do this?

I've tried instead of:
countZ++;

writing:
countZ + 15;

but was unsuccessful. I also tried this:
if (countZ < imagesB.length * 15) {
 countZ + 15;
}

Which didn't work either.

I have this rather unwieldy section of code:
   image(imagesB[countB + 1], xpos - 15, ypos + 400);
   image(imagesB[countB + 2], xpos - 30, ypos + 400);
   image(imagesB[countB + 3], xpos - 45, ypos + 400);
   image(imagesB[countB + 4], xpos - 60, ypos + 400);
   image(imagesB[countB + 5], xpos - 75, ypos + 400);
   image(imagesB[countB + 6], xpos - 90, ypos + 400);
   image(imagesB[countB + 7], xpos - 105, ypos + 400);
   image(imagesB[countB + 8], xpos - 120, ypos + 400);
   image(imagesB[countB + 9], xpos - 135, ypos + 400);
   image(imagesB[countB + 10], xpos - 150, ypos + 400);
   image(imagesB[countB + 11], xpos - 165, ypos + 400);
   image(imagesB[countB + 12], xpos - 180, ypos + 400);
   image(imagesB[countB + 13], xpos - 195, ypos + 400);
   image(imagesB[countB + 14], xpos - 210, ypos + 400);
   image(imagesB[countB + 15], xpos - 225, ypos + 400);
   image(imagesB[countB + 16], xpos - 240, ypos + 400);
   image(imagesB[countB + 17], xpos - 255, ypos + 400);
   image(imagesB[countB + 18], xpos - 270, ypos + 400);
   image(imagesB[countB + 19], xpos - 285, ypos + 400);
   image(imagesB[countB + 20], xpos - 300, ypos + 400);
   image(imagesB[countB + 21], xpos - 315, ypos + 400);
   image(imagesB[countB + 22], xpos - 330, ypos + 400);
   image(imagesB[countB + 23], xpos - 345, ypos + 400);

which I wanted to simplify a little by using a variable increment. Or at least I was going to try.

Any help is appreciated.
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sw01
Re: How do you make increments greater than 1
Reply #1 - Nov 25th, 2008, 11:29pm  
You are adding, but not committing the resultant value to the variable.

Either:
x = x + 15;

or try the short hand

x += 15;
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