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Index › Programming Questions & Help › Syntax Questions › save rgbstring in an array
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save rgbstring in an array (Read 499 times)
corteingles
save rgbstring in an array
May 23rd, 2008, 3:04pm  
hello
i'm desperately juggling with array-syntax.
i simply want to create a new array with 6 different color values which i can later access through
background(colorarray[0]...) something
in every arrayposition a string lookalike 255,0,255 should be stored but I'm completely confused by getting various errors could somebody give me a hint on an elegant solution of storin g a fixed amount of given colors to be accessed at any time easily?
thanks for reading and helping
ingles (:
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JohnG
Re: save rgbstring in an array
Reply #1 - May 23rd, 2008, 3:27pm  
Do you need the colours to be stored as strings for any particular reason?

It'd be easier to store colors in an array of colors:

Code:
color[] colors;

void setup()
{
  //...
  colors=new color[6];
  color[0]=color(255,0,255);
  color[1]=color(255,255,0);
  color[2]=color(0,255,255);
  // etc for [3] [4] and [5].
}

void draw()
{
  background(colors[0]);
}
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corteingles
Re: save rgbstring in an array
Reply #2 - May 23rd, 2008, 4:02pm  
thanks JohnG
i was thinking a bit too complicated thanks for the hint using color() but still I get the "Expecting RBRACK, found '0'" error by using your piece of code... I'm a bit confused about the general array syntax in a way... maybe there is any need for a for-loop?!
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PhiLho 
Re: save rgbstring in an array
Reply #3 - May 23rd, 2008, 4:43pm  
JohnG probably typed in the browser, he made a little mistake, init. is colors[0] (resp. 1, 2, etc.), not color[0].

And yes, 'for' loops are a natural way to use arrays.
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JohnG
Re: save rgbstring in an array
Reply #4 - May 23rd, 2008, 4:44pm  
oops I missed an s off the color[ part, it shoudl be colors[0] etc..
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corteingles
Re: save rgbstring in an array
Reply #5 - May 26th, 2008, 12:28pm  
oh thx
now everything is working concerning this but I'm stuck at a further problem.
I have another array which randomly chooses colors for a determined amount of objects out of this colorarray.
but I'm drawing the objects(rects) with 2 for-loops for columns and rows.
But if i want to assign every object from 0-20 (e.g. in a 5x4 grid) its own color, i have to assign some kind of ID to every object that my draw-function can look like this in the end:
       fill(colors[definedcolorarray[ID].dc]);

how can i assign a ID to every object?
during creating the array like
 for(int i=0; i<(rows*cols); i++){
   rectcolorarray[i] = new rectcolor();
}

I'm really stuck...
plz help
or ask for the whole code if necessary
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PhiLho 
Re: save rgbstring in an array
Reply #6 - May 26th, 2008, 1:39pm  
I am not sure what you are trying to do, but this code snippet works:
Code:
color[] colors;

int COLOR_NB = 6;
int ROW_NB = 5, COL_NB = 4;
int SIZE = 20, MARGIN = 5;
Rect[] rect = new Rect[ROW_NB * COL_NB];

void setup()
{
  size(200, 200);
  int c = 0;
  colors = new color[COLOR_NB];
  colors[c++] = #FF0000;
  colors[c++] = #00FF00;
  colors[c++] = #0000FF;
  colors[c++] = #FFFF00;
  colors[c++] = #00FFFF;
  colors[c++] = #FF00FF;

  for (int i = 0; i < ROW_NB * COL_NB; i++)
  {
    rect[i] = new Rect(int(random(0, COLOR_NB)));
  }
}

void draw()
{
  for (int i = 0; i < ROW_NB; i++)
  {
    for (int j = 0; j < COL_NB; j++)
    {
	fill(colors[rect[i * COL_NB + j].colorIndex]);

	rect(MARGIN + (SIZE + MARGIN) * i, MARGIN + (SIZE + MARGIN) * j, SIZE, SIZE);
    }
  }
}

class Rect
{
  int colorIndex;
  Rect(int _colorIndex)
  {
    colorIndex = _colorIndex;
  }
}

Now, you can put more information in Rect, like its coordinates and color index, and let this object draw itself.
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