Processing 1.0 - Processing Discourse - arrange two dimension array

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arrange two dimension array (Read 292 times)

sethiank

arrange two dimension array
May 4^th, 2008, 12:18am

Hello,

I am a beginner with processing, and due to limited knowledge I'm not able to rearrange simple list of array using array functions available in processing. It would be a great help if you could show me the way. Here is the problem

I have two dimension array like this

float notes[][] = {{60,1.0},
{64,1.0},
{62,1.0},
{65,1.0},
{67,1.0},
{71,3.0},
{69,1.0},
{72,4.0}};

I want to rearrange the order of notes array according to a sequence from another variable hit[i] which could be (4, 7, 1, 0, 3)

The result should be
newNotes = {{67,1.0},
{72,4.0},
{64,1.0},
{60,1.0},
{65,1.0}}

I tried with arraycopy and subset to get each elements for example hit[7] = {72, 4.0} but how can I put them together.
concat doesn't work, Is there any other way?

Thanks a lot!!!

jeanine

Re: arrange two dimension array
Reply #1 - May 4^th, 2008, 1:35am

I also am a beginner at this. The following works, though it does require declaring the second array with the size of the change array:

int[] change = {4,7,1,0,3};
float[][] notes = {
{60,1.0},
{64,1.0},
{62,1.0},
{65,1.0},
{67,1.0},
{71,3.0},
{69,1.0},
{72,4.0}};
float[][] newNotes = new float[change.length][2];
int i;
for (i=0;i<change.length;i++) {
newNotes[i]= notes[change[i]];
}

println("newNotes.length is "+newNotes.length);
for (i=0;i<change.length;i++){
println(" ");
print("newNotes["+i+"][0] "+newNotes[i][0]);
print(" ");
print("newNotes["+i+"][1] "+newNotes[i][1]);
}

An alternative is to make the second array big enough and just use part of it.

Some on-line posts say that dynamic arrays are bad...

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