Ok, this is a fairly major and crucial point in programming.

1.) to make a new array holding integers (all spots initialized to 0) of a certain length, you can do:

int[] data = new int[5];

will make data be {0,0,0,0,0}.

You can also use a variable:
int n = 5;
int[] data = new int[n];

is the same as the above.

Also,
int[] data = new int[test.length()]

^ makes a new array of length test.length().

Now, if you truly need a "dynamic" array, where it can hold a varying amount of data, you could just make the array inordinately long (say, 1000 units) and then only use the first few. But, this is wasteful.

You need what is known as a Collection, and they are made for you in java.util. (Though, you could design your own.)

The simplest is "ArrayList".

ArrayList data = new ArrayList();
data.add(1);
data.add(2);

data is now {1,2}.

to get back your stored data,
data.get(n)

So, the above data arraylist would return 1 on .get(0) and 2 on .get(1).

Was I clear enough?

@ leanderlike
Unfortunately it seems that ArrayLists currently won't take ints.

Check out this thread covering the same topic. It may be a bit confusing with all the talk about Java versions, but towards the end, fry recommends to go with a standard int array and using expand() to change its length when needed.

Hope this helps.

@ taifunbrowser
That's a great little rundown on arrays.

Quote:

Thanks for the advice!

In case you're confused, what's the difference between int and Integer
And here's what the Java Reference has to say about Integer.