Hi everyone,
I am new to java.
I have a question?
How can I store in to an array the values that the user enter, so later I can compare the two sets of array that the user enter.
Thanks

Ok, the user needs to enter two sets, then main will call another class named IntergerSet where both sets are going to be compered.
Therefore I need to store the sets of values in two different sets.

This is what I have till know:

import java.util.Scanner;
public class UniversalSet
{
public static void main(String[] args)
{
Scanner input = new Scanner (System.in);

System.out.println("Welcome to the" +
                                " Universal Set\n");
     
   System.out.print("This program is going to find "  
                + "the union or intersection of any two "
                + "sets you enter\nPlease enter how many "
                + "values on set 1: ");
   int value1 = input.nextInt();
   
   System.out.print("Now please enter the first "
                + "set: ");
   for(int i=0; i<=value1 ;i++)
   {
//cannot find symbol method parseInt(int)->
             int userSetArray1[] = Integer.parseInt
                                      (userSetArray1[i]);
   }
   
   System.out.print("Please how many values on set "
                + "2: ");
   int value2 = input.nextInt();
   
   System.out.print("Now enter the second set: ");
   for(int i=0; i<=value2 ;i++)
   {
//cannot find symbol method parseInt(int)->
             int userSetArray2[] = Integer.parseInt
                                      (userSetArray2[i]);
   }
   
//cannot find symbol variable userSetArray1 and
//userSetArray1->  
       IntergerSet elementSet = new IntergerSet
                           (userSetArray1, userSetArray2);
   }
}

more important, it looks like you're just writing java code... processing isn't a particularly good environment for writing straight java code, and using System.in/System.out (or Scanner for that matter). processing is designed for building visual things and interactive works, so doing terminal-based stuff isn't gonna be fun.