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Index › Programming Questions & Help › Syntax Questions › render java geometry
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render java geometry (Read 915 times)
adamdoul
render java geometry
Jul 24th, 2007, 4:13pm  
Hi there,

Is there a way to render Java geometry classes?
In Java you have to write smt like:

g2.draw(new Rectangle2D.Double(x, y,rectwidth,rectheight));

Is there a similar way in processing to render Java primitives and shapes geometries with generalPath?

Thanks Smiley
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V
Re: render java geometry
Reply #1 - Jul 25th, 2007, 10:26am  
there are a few calls you can use to draw basic geometry/shapes.

rect( x, y, size, size )
ellipse( ... )
sphere (... )
box( ... )
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Victor Martins | www.pixelnerve.com/v
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adamdoul
Re: render java geometry
Reply #2 - Jul 26th, 2007, 10:55pm  
yes I know these.. the problem is that I have geometries created with the java.awt.geom.GeneralPath and the java.awt.Polygon classes. I was wandering if there is a way to render these geometries.

But thanks a lot anyways..
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JohnG
Re: render java geometry
Reply #3 - Jul 26th, 2007, 11:29pm  
The only way to render them is to step through them yourself and convert their meaning to processing meaning. There is no automatic way to draw them.

e.g. if it's a Rectangle2D, get the position/size out, and pass that to rect(...);
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fry
Re: render java geometry
Reply #4 - Jul 27th, 2007, 12:10am  
you can use a PathIterator and map the calls to beginShape() and endShape(). i think there's an example elsewhere on the board that shows how to do this with font glyph shapes.
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adamdoul
Re: render java geometry
Reply #5 - Jul 29th, 2007, 4:16am  
thanks a lot! Smiley

btw, I came up with that solution based on the pathIterrator:


Code:

 class myPolygon{  
  java.awt.geom.GeneralPath trace = new GeneralPath();
  
  myPolygon(float[] x,float[] y){ //constructor from points
    trace.moveTo(x[0],y[0]);
    for (int i=1; i< x.length;i++){
	trace.lineTo(x[i],y[i]);
    }
    trace.closePath();
  }


  void draw(){
    PathIterator pi = trace.getPathIterator(null);
    float[] pts = new float[2];
    while (!pi.isDone()) {
	int type = pi.currentSegment(pts);
	if (type == PathIterator.SEG_MOVETO){
	  beginShape();
	  vertex(pts[0],pts[1]);
	}
	if (type == PathIterator.SEG_LINETO) { // LINETO
	  vertex(pts[0],pts[1]);
	  //println(pts[0]+","+pts[1]);
	}
	if (type == PathIterator.SEG_CLOSE) {
	  endShape();
	}
	pi.next();
    }
  }
}


that will do. Smiley I hope it's not terrible.
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