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Index › Programming Questions & Help › Syntax Questions › floor() does not take double
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floor() does not take double (Read 773 times)
andykitchen
floor() does not take double
Jan 14th, 2007, 11:27am  
I get an error on the following code,
running 0123 BETA on Linux.

--code

double x = 100.2;
floor(x);

--error

/tmp/build4147.tmp/Temporary_3129_7309.java:2:1:2:8: Semantic Error: No applicable overload for a method with signature "floor(double)" was found in type "processing.core.PApplet". Perhaps you wanted the overloaded version "int floor(float $1);" instead?

--end

Thank you for your time.
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JohnG
Re: floor() does not take double
Reply #1 - Jan 14th, 2007, 2:13pm  
If you want to work with doubles, use Math.floor(x); from the Java maths functions.

See: http://java.sun.com/j2se/1.4.2/docs/api/java/lang/Math.html for a full reference.
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fry
Re: floor() does not take double
Reply #2 - Jan 14th, 2007, 4:51pm  
see also:
http://processing.org/discourse/yabb_beta/YaBB.cgi?board=Syntax;action=display;num=1168789838
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