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Index › Suggestions & Bugs › Software Bugs › pmouseX in mouseDragged()
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pmouseX in mouseDragged() (Read 1501 times)
wxs
pmouseX in mouseDragged()
Oct 16th, 2005, 1:44am  
Hello,
I'm writing a program which creates a new object based on the velocity of the mouse when released. The problem is in mouseReleased() mouseX and pmouseX seem to be the same. This means that I needed to make a mouseDragged() method as follows:

    void mouseDragged() {
       pMouseX = pmouseX;
       pMouseY = pmouseY;
    }

and then refer to those from mouseReleased(). Is there a better way to do this?
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mark hill
Re: pmouseX in mouseDragged()
Reply #1 - Oct 16th, 2005, 3:52pm  
You could just try and set a flag that gets picked up as part of the draw method. This might also save on sync issues, if any still remain?

Code:

void draw() {

if(released) {
  released = false;
  println(mouseX+": "+pmouseX);
  }
}


boolean released = false;

void mouseReleased() {
released = true;

}
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fry
Re: pmouseX in mouseDragged()
Reply #2 - Oct 16th, 2005, 6:55pm  
i've responded to your bug report here:
http://dev.processing.org/bugs/show_bug.cgi?id=170

for the time being there's a workaround, though maybe i can get this into 0094.
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fry
Re: pmouseX in mouseDragged()
Reply #3 - Sep 12th, 2006, 9:00pm  
now altered (fixed?) for 0116.
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