It is specified as a 32bit *unsigned* number, however, the int type in Java is signed.  As far as memory is concerned, unsigned and signed are the same thing, it's simply a matter of how the number is displayed.  The details on how signed/negative numbers work in binary I will leave as extended reading.

What matters here is you need to do is get each of the 8bit numbers from that 32bit number.  You can do this as follows (I am assuming the numbers are in the format: 0xAAHHSSBB, and the color is stored in an int variable called c.

int alpha = (c>>24)&0xFF; // Shift the number 24 bits (3 bytes) to the right, and limit it to 0~255.
int hue = (c>>16)&0xFF; // Shift the number 16 bits (2 bytes) to the right, and limit it to 0~255.
int alpha = (c>>8)&0xFF; // Shift the number 8 bits (1 byte) to the right, and limit it to 0~255.
int alpha = c&0xFF; // Limit the number to 0~255.

Although, if I recall, doesn't processing return float type for HSB?

Marcello

Thanks I'll give it a shot
I appreciate the quick response