 |
Author |
Topic: Finding the largest value of an array (Read 1834 times) |
|
REAS
|
Finding the largest value of an array
« on: Oct 31st, 2002, 12:52am » |
|
// The maxVal() method returns the largest value of an array
int[] numbers = { 90, 150, 30 };
void loop()
{
int largestNum = maxVal(numbers);
println(largestNum);
}
int maxVal(int[] testArray)
{
int maximum = Integer.MIN_VALUE; //initialize to the smallest int
for(int i=0; i<testArray.length; i++) {
maximum = max(testArray[i], maximum);
}
return maximum;
}
/** An alternative maxVal() method, faster
int maxVal(int[] testArray)
{
int maximum = Integer.MIN_VALUE; //initialize to the smallest int
for(int i=0; i<testArray.length; i++) {
if (testArray[i] > maximum) {
maximum = testArray[i];
}
}
return maximum;
}
*/
|
|
|
|
|
fry
|
Re: Finding the largest value of an array
« Reply #1 on: Oct 31st, 2002, 4:06am » |
|
and if you really wanna be a weenie, this one is (just slightly) improved:
int maxVal(int[] testArray)
{
// initialize to the first element, since that's
// what will be assigned the first time through
// the loop anyways, in the previous version
int maximum = testArray[0];
// then start the loop at 1 instead of 0, because
// the 0th element has already been 'checked'
for(int i = 1; i < testArray.length; i++) {
if (testArray[i] > maximum) {
maximum = testArray[i];
}
}
return maximum;
}
|
|
|
|
|
|
