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Topic: new BImage from non-contiguous pixel selection? (Read 230 times) |
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sspboyd
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new BImage from non-contiguous pixel selection?
« on: Apr 21st, 2004, 11:32pm » |
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Hello, again. New day, new question for the Syntax forum.
Is it possible to create a new BImage from a non-contiguous selection of pixels.
For example, I'd like to select 4 squares (50x50) from an image and create a new image (100x100) from the selected squares.
Pseudo code
Code:pix1 = pixels(0,0,10,10);
...
pix4 = pixels(50,50,10,10);
BImage tile = pix1 at 0,0 + pix2 at 0,50 + pix3 at 50,0 + pix4 at 50,50; |
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I've been looking through the image related functions and nothing is immediately jumping out at me as the answer.
Thank you, again!
steve
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gmail.com w/ sspboyd username
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TomC
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Re: new BImage from non-contiguous pixel selection
« Reply #1 on: Apr 22nd, 2004, 12:54am » |
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BImage.replicate() copies regions from one image to another: http://processing.org/reference/replicate_.html
It's not all that clear in the reference (yet, I assume) but to use this on two or more images, use...
Code:
BImage srcImg = loadImage("a50x50img.jpg");
BImage target = new BImage(100,100);
target.replicate(srcImg,
0, 0, 50, 50, // whole of srcImg
50, 50, 100, 100); // bottom-right of target
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sspboyd
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Re: new BImage from non-contiguous pixel selection
« Reply #2 on: Apr 22nd, 2004, 5:52am » |
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Thanks Tom! That works great.
I worked out a way of doing it with pixel colour values but your way is much better.
Here's how Im using it:
Code:BImage bgTile = new BImage(tileW*2, tileH*2);
for(int i=0;i<2;i++){
for(int j=0;j<2;j++){
int randImg = int(random(tiles.length));
bgTile.replicate(tiles[randImg],
0,0,tileW,tileH,
j*tileW,i*tileH,tileW+(j*tileW), tileH+(i*tileH));
}
} |
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gmail.com w/ sspboyd username
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