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Topic: *beware newbie* why the color() is not working? (Read 331 times) |
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lunetta
 
 
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*beware newbie* why the color() is not working?
« on: Mar 21st, 2004, 10:38pm » |
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Hi
I have a really dumb question;
Why this does not work?
color test = color(204, 50, 50);
void setup() {
size (200,200);
}
void loop() {
fill (test);
rect (0,0,100,100);
}
sorry for bothering with this extremely simple thing...
if the color is a primitive datatype, why can't a declare a global assigning a RGB value? the hex notation works...
Thanks!
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fry
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Re: *beware newbie* why the color() is not working
« Reply #1 on: Mar 21st, 2004, 10:58pm » |
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because color() is a function, and it's dependent on the current colorMode(), and the colorMode() is not set until you're inside of setup().
but as you point out, this is a real nuisance, so i think i'll modify it to work as you have it in your program, just with colorMode(RGB, 255) since that's what most people are using.
sorry for the confusion..
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lunetta
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Re: *beware newbie* why the color() is not working
« Reply #2 on: Mar 22nd, 2004, 6:17am » |
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Thanks!!
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