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Topic: all splitstrings are created equal (or are they?) (Read 233 times) |
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Euskadi
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all splitstrings are created equal (or are they?)
« on: Feb 24th, 2004, 9:26pm » |
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This code snippet should compare to String arrays and find matches... problem is nothing ever matches, even if the same string is split into two arrays.
So I added a println so I can see what the strings are and a second check to see if they are ==.
Code:
void setup(){
String str1 = "One;Two";
String[] numID = splitStrings(str1, ';');
String[] numEscStr = splitStrings(str1, ';');
int numEscNum[] = new int[2];
for(int en = 0; en < numID.length; en++){
for(int es = 0; es < numEscStr.length; es++){
println("|" + numEscStr[es] + "|" + numID[en] + "|"); //show me the strings
println(numEscStr[es] == numID[en]); // should sometimes be true
if(numEscStr[es] == numID[en]){
numEscNum[es] = en;
println(es + " " + en);
}
}
}
}
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This is the output... am I missing something?
|One|One|
false //HUH?
|Two|One|
false
|One|Two|
false
|Two|Two|
false //HUH?
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TomC_
Guest
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Re: all splitstrings are created equal (or are the
« Reply #1 on: Feb 24th, 2004, 10:58pm » |
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Strictly speaking, in Java == tests the identity of objects. The Strings you are comparing aren't the same object, so they aren't identical.
String has a custom equals method to compensate for this. Use string1.equals(string2) to test for lexicographic equality instead.
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Euskadi
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Re: all splitstrings are created equal (or are the
« Reply #2 on: Feb 25th, 2004, 2:32am » |
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arf. ok, I knew that at one time. thanks!
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