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Topic: I have errors when println() is commented out (Read 319 times) |
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RoBo
Guest
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I have errors when println() is commented out
« on: May 13th, 2003, 10:13pm » |
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Ciao,
I put two println() commands in for debugging, and now I can't remove them without a hassle. The comments (after the commands) explain my trouble. Please take a vidy droogs,
RoBo
int xpts[];
int ypts[];
int maxNpts;
int nPts;
int width=800;
int height=600;
void setup() {
size(width, height);
noBackground();
nPts = 0;
maxNpts = 4*width;
xpts = new int[maxNpts];
ypts = new int[maxNpts];
for (int i=0; i<maxNpts; i++) {
xpts[i] = 0;
ypts[i] = 0;
}
}
void loop() {
while(mousePressed == true) {
xpts[nPts] = mouseX; //error points here
ypts[nPts] = mouseY;
println(nPts);
//I get an arrayIndexOutOfBoundsException if I comment this out or move it outside the loop!
nPts++;
}
}
void mouseReleased(){
int tote=0;
if (nPts > 0){
for (int i=1; i<nPts; i++){
tote += sqrt(sq(xpts[i] - xpts[i-1])+sq(ypts[i] - ypts[i-1]));
stroke(abs(2.5*(xpts[i] - xpts[i-1])), 0, abs(2.5*(ypts[i] - ypts[i-1])));
line(xpts[i-1], ypts[i-1], xpts[i], ypts[i]);
println(tote);
//I have problems with the line always starting at the origin if I comment this out
}
nPts=0;
for (int i=0; i<maxNpts; i++) { //clear
xpts[i] = 0;
ypts[i] = 0;
}
}
}
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arielm
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Re: I have errors when println() is commented out
« Reply #1 on: May 24th, 2003, 1:27am » |
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actually, println() is making the execution 100 times slower than if it were'nt there, so it gives the illusion that everything is okay, but if you wait for a while, you will still get the ArrayIndexBound... exception...
the problem is that the while() statement inside loop() is an infinite loop because the mousePressed variable is only updated (something like) once a frame...
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Ariel Malka | www.chronotext.org
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