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Topic: float() in parentheses (Read 1842 times) |
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narain
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float() in parentheses
« on: May 8th, 2004, 12:11pm » |
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This is very strange.
float u = float(x)/width; works.
float u = (float(x)/width); doesn't work: "unexpected token: float".
float u = (x/float(width)); works!
Apparently Processing finds it illegal for float() to be the first token in a parenthesized expression.
I guess it gets confused expecting (float... to be a typecast.
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fry
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Re: float() in parentheses
« Reply #1 on: May 8th, 2004, 8:35pm » |
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yeah, more of these have been popping up recently. thanks for the details on what's working and what's not.. that's really helpful.
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