 |
Author |
Topic: understanding Java's regex implementation (Read 750 times) |
|
kevinP
|
understanding Java's regex implementation
« on: Jun 12th, 2004, 7:13pm » |
|
Hi,
I have:
Code:
// Java regex demo
import java.util.regex.*; // import regex package
class regexDemo extends BApplet {
void draw()
{
// For one-time matches
boolean a = Pattern.matches("a*b", "babaabaaaaaa"); //
println("a: Find 'a*b' in 'babaabaaaaaa' - " + a);
boolean b = Pattern.matches("a*b", "bbbbbbbb"); // 'a' zero or more times, followed by b...
println("b: Find 'a*b' in 'bbbbbbbbb' - " + b);
}
} // end of sketch class
|
|
And it returns false for both cases. But shouldn't the second match return 'true'? (Hmmm, actually shouldn't both return 'true'?)
-K
|
| « Last Edit: Jun 12th, 2004, 7:16pm by kevinP » |
|
Kevin Pfeiffer
|
|
|
TomC
|
Re: understanding Java's regex implementation
« Reply #1 on: Jun 12th, 2004, 8:31pm » |
|
No, I don't think so. This matches method will return true only if the whole string matches the given regular expression. It isn't searching for a substring.
|
|
|
|
|
kevinP
|
Re: understanding Java's regex implementation
« Reply #2 on: Jun 12th, 2004, 10:35pm » |
|
Ah, of course! (dumb of me)
I needed to validate some input and noticed that the tech notes include little on parsing/matching, so I'll try to post a little demo later maybe.
-K
|
Kevin Pfeiffer
|
|
|
|
