And this prints numbers around 48-58 as x in the log. I'm dumbfounded as to why it wouldn't give me the right characters from the String pi. Thank you for your help in advance.

Edit: I realized the int(pi.charAt(i)) is not working, as this results in the utf-8 character code of the given number from 0 to 9, which are 48-57. Of course, I can work around this, but would still be best to see how this should be done properly.

link letter "a" to an ellipse link letter "b" to a rectangle link letter "c" to a triangle

so if the string is "abc" I will have "ellipse, rect and triangle" on the screen; so if the string is "bca" I will have "rectangle, triangle and ellipse" on the screen; so if the string is "cab" I will have "triangle, ellipse and rectangle" on the screen; ... and so on.

Could you help me?

Thank you very much.

obviously an old problem. It occurs in different forms.

E.g. in a scrabble game we have to hand out letters to the players. But they are not distributed evenly over the Alphabet, so there are not as many Qs than Es in the game (reflecting the distribution of letters in normal English texts).

Let's therefore assume, I make a char array, where this distribution is reflected, so it's

EEEEEEEEEQAAAAAAMMOO or so.

Now retrieving elements from this list randomly:

When I retrieved a letter I can't retrieve it again. I can replace it with a character that is a stop sign like #.

EEEEE#EEEQAAAAAAMMOO

But then when retrieving a letter later in the game, most slots hold #-signs.

##E################O#

So a typical random like

randomNumberIndex = int(random(listOfLetters.length())); would most times fail, so I would have to repeat it until hitting a letter. Bad.

But what is the most efficient way of solving this? An ArrayList and then shorten the ArrayList ?

Thanks!

Best, Chrisir ;-)

Is there a workaround that'll give me what I want??

Cheers

char[] explode(String s) { String theString = s; char[] c = new char[theString.length()]; for (int i = 0; i < theString.length(); i++) { c[i] = theString.charAt(i); return c[i]; } }

I also want to write a function that behaves like the above one in reverse. Taking an array of characters as input and returns a String consisting of all the characters in the array glued together. For example, returning ("Dirk") after inputting the array {'D', 'i', 'r', 'k'}.

I want to make a program that includes a function. The function should reverse a word. For example if I type in Hello, it should end up with olleH. My question is how the code would look like for this program.

Thank you in advance, Lugi5000

how do i address characters in string? name[0][4] should be 1 name[1][4] should be 2 what is the proper syntax, this worked in C

When I click play, I want the image to be at the stage when the mouse is at the right side of the screen. And as the user is typing, the image goes from high tot left (pixelated to clear image). How to connect the image to keyboard?

//variables for message function String message = "Lorem ipsum dolor sit amet, consectetur adipiscing elit. Aliquam vel quam fermentum, blandit nulla vel, adipiscing sapien. Pellentesque nunc lectus, vestibulum a sollicitudin ac, vulputate vitae libero. Duis ut consectetur quam, ullamcorper faucibus est. Quisque quis dui ante. Vivamus ullamcorper, felis et feugiat faucibus, augue odio lacinia est, et tristique neque ligula eget mi. Morbi et nulla leo. Integer semper nibh erat, ac rutrum ante hendrerit id."; float textleft = 50, texttop = 50; float charw = 8, charh = 13; int lettersPerLine = 90; float xmargin = 400, ymargin = 750; int progress = 0; int[] asciivalues; //use this line to convert string to int[]

PImage img; int grid = 5;

import processing.video.*; Capture cam;

void setup() { size(displayWidth, displayHeight); textFont(createFont("Courier", 14), 14);

asciivalues = int( message.toCharArray() ); //use this line to convert string to int[]

cam = new Capture(this, width, height, 30); cam.start();

img = loadImage("01.png"); img = cam; background(0); smooth();

}

float getXPosition(int index) { return index%lettersPerLine * charw + xmargin; } float getYPosition(int index) { return int(index/lettersPerLine) * charh + ymargin;

}

void draw() {

// background(255);

timer(120);

picture(); pix(); message(); //rect(0, -180, width, height);

}

//message to be typed function void message() {

for (int i = 0; i < message.length (); i++) { fill(0); if (progress >= i) fill(100); if (progress == i) fill(255, 0, 0); textSize(14); text(message.charAt(i), getXPosition(i), getYPosition(i)); }

}

void keyPressed() { if (int(key) >= int(' ') && int(key) <= int('z')) { if (progress < message.length() && key == asciivalues[progress]) { progress++; int percentDone = floor(float(progress) / float(message.length())*100); println(percentDone); } } }

//timer function void timer(int interval) {

String time = "Time"; int t;

//background(255); t = interval - int(millis()/1000); time = nf(t, 2); if (t < 0) { time = ""; textSize(100); fill(255, 0, 0); noStroke(); text("STOP", width/2.5, height/1.12); message = ""; } text(time, width0.15, height0.9); }

//image function

void picture() { if (cam.available()) { cam.read(); } image(cam, 0, -180); //filter(GRAY); //filter(INVERT); //filter(THRESHOLD, 0.50); } void mousePressed() { image(cam, 0, 0); filter(GRAY); //filter(THRESHOLD, 0.50);

saveFrame("/Users/aminatayyub/Desktop/DC_Final/text_perc_cam_eurika_/data/01.png"); cam.stop();

}

//pixel to image function void pix() {

grid = mouseX+1; // Pick a random point

for (int x = 1; x < width; x+=grid) { for (int y = 0; y < height; y+=grid ) { int loc = x + y*img.width;

  // Look up the RGB color in the source image
  img.loadPixels();
  float r = red(img.pixels[loc]);
  float g = green(img.pixels[loc]);
  float b = blue(img.pixels[loc]);
  float gray = brightness(img.pixels[loc]);

  noStroke();

  // Draw an ellipse at that location with that color
  fill(r, g, b, 100);
  fill(gray);
  rect(x, y, grid, grid);
}

}

}

For example:

for (int i = 0; i < string.length; i++) { character[i] = ______________; }

String sentence = "The unusually quick brown fox jumps over the lazy family dog repeatedly.";
println(sentence.indexOf("a"));
println(sentence.indexOf("e"));
println(sentence.indexOf("i"));
println(sentence.indexOf("o"));
println(sentence.indexOf("u"));
noLoop();

I have an array of Strings, {a,b,c,b,a,d,a,c,a}. I wanted to sort and replace them with integers, and change it as {0,1,2,1,0,3,0,2,0}

As the first step I tried removing the repeating elements from the array and made another array of strings {a,b,c,d}. Then I used a for loop and assigned values for these strings as {0,1,2,3}.

Now I wanted to replace the individual members in the first array of strings, where "a" is replaced with "0", "b" with "1", "c " with "2" and "d" with "3", and make an array {0,1,2,1,0,3,0,2,0}

String [] name = {"a", "b", "c", "b", "a", "d", "a", "c", "a"};

IntDict sortedName;
IntDict finalNameList;


void setup() {
  size(600, 600);
  smooth();

  sortedName = new IntDict();
  finalNameList = new IntDict();


  for (int i=0; i<name.length; i++) {
    finalNameList.increment(name[i]);
  }

  String [] names = sortedName.keyArray(); //// sorted array of strings {a,b,c,d}

  for (int i=0; i<names.length; i++) {
    finalNameList.set(names[i], i);
  }

  int [] values = finalNameList.valueArray(); ///// assigned values for a,b,c,d-- 0,1,2,3


  ////// now i wanted to replace the strings in the first array, name with the integers

  for (int i =0; i<name.length; i++) {
    name[i]= name[i].replaceAll(names[i], i-names.length);

    println(name[i]);
  }
}


void draw() {

  background(125);
}

would be great if someone can help me with this. many thanks in advance :)

• Check first character in a string
• Check what that character is.
• Add 1 to counter (could use an array to store the frequency of each character)
• Move on to the next character in the string
• and so on..

Essentially I am trying to figure out a way of counting the frequency of each different character in a string.

I was able to do this using if/else statements for each letter of the alphabet but ideally I would like a better way of doing this.

Heres what I have so far:

      String yourString = msg;
      char[] allChars = new char[yourString.length()];
      for (int i = 0; i < yourString.length (); i++) {
        allChars[i] = yourString.charAt(i);
        String character = str(allChars[i]);

        for (counter=0; counter < alpha.length; counter++) {
          if (character.equals(alpha[counter]) == true ) {
            count[counter] = count[counter]+1;
          }
        }
      println("The number of A is" + count[0]);
      }

alpha is a character array containing the individual letters of the alphabet count is an array where I am trying to store the values i.e:

• count[0] would equal the number of times the letter A appears in the string
• count[1] would equal the number of times the letter B appears in the string

Any help would be great! thanks!

String[] lines;
String dato[];
int index = 0;

void setup() {
  size(200, 200);
  background(0);
  lines = loadStrings("abra.txt");

  if (index < lines.length) {
    dato = split(lines[index], ',');
    index=index+1;
    println(dato);
  }

  int []charFreqs = new int[256];
  for(char c: dato.toCharArray){
    charFreqs[c]++;
  }
}

How can i achieve this?