TimeoutException I need stop code funcion. Java/Processing

anthony20

Hello,

I have a problem with a piece of code, sometimes it is too slow. The code is responsible for testing a printer, the problem is that if the printer is offline, the program crashes for 15-20 seconds. I want that if after 2 seconds has not done the task, jump the code.

Something like a break if the time exceeds two seconds

I think it can work with try {} catch (TimeoutException e) {} but, I not know how could do exception.

I've been looking Thread and TimeoutException but not how to do.

Is there any way to do this?

thanks in advance

anthony20

Isn't there a code processing for what I want to do?

This is not a hardware problem, it is an attempt to fix a bug in java.

Eeyorelife

https://forum.processing.org/two/discussion/7312/how-can-i-throw-exception-from-my-code

anthony20

Thanks for anwswer Eeyorelife.

I can solved problen with Thread

    void setup(){
            ThereadOK AAA = new ThereadOK("testing");
            AAA.start();   
        }
        int i = 0;
    void draw()
    {
      println(i); i++; delay(500);
    }


    public class ThereadOK extends Thread {
        public ThereadOK(String str) {
            super(str);
        }
        public void run() {
          try{   
            println(getName());delay(10000);println(getName());
          }catch(Error e){}
        }
    }

It sample code mayby can help in future questions.