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text input problem

[1 Reply]
- 02-Jan-2013 06:13 AM
- Forum: Programming Questions
Hi I found the following code on the internet that allows the user to input date:
2. String typedText = "your text here";
4. PFont font;
6. void setup() {
7. size(400, 400);
8. font = createFont("Helvetica", 18);
10. }
12. void draw() {
13. background(255);
14. fill(255,0,0);
15. textFont(font,18);
16. line(0,0,200,200);
17. // this adds a blinking cursor after your text, at the expense of redrawing everything every frame
18. text(typedText+(frameCount/10 % 2 == 0 ? "_" : ""), 35, 45);
19. }
21. void keyReleased() {
22. if (key != CODED) {
23. switch(key) {
24. case BACKSPACE:
25. typedText = typedText.substring(0,max(0,typedText.length()-1));
26. break;
27. case TAB:
28. typedText += " ";
29. break;
30. case ENTER:
31. case RETURN:
32. // comment out the following two lines to disable line-breaks
33. typedText += "\n";
34. break;
35. case ESC:
36. case DELETE:
37. break;
38. default:
39. typedText += key;
40. }
41. }
42. }
For this to work properly a background(255); in draw{} is executed every loop to 'refresh' the sketch and draw the updated text. Is there a simple way how this can be done without using background(255) in the draw method?

In other words if I modify the program above so that it generates a random number as show below, the number will be show in my sketch (it is only shown when background(255) is removed).
2. String typedText = "your text here";
4. PFont font;
6. void setup() {
7. size(400, 400);
8. font = createFont("Helvetica", 18);
9. randomNumber();
10. }
12. void draw() {
13. background(255);
14. fill(255,0,0);
15. textFont(font,18);
16. line(0,0,200,200);
17. // this adds a blinking cursor after your text, at the expense of redrawing everything every frame
18. text(typedText+(frameCount/10 % 2 == 0 ? "_" : ""), 35, 45);
19. }
21. void keyReleased() {
22. if (key != CODED) {
23. switch(key) {
24. case BACKSPACE:
25. typedText = typedText.substring(0,max(0,typedText.length()-1));
26. break;
27. case TAB:
28. typedText += " ";
29. break;
30. case ENTER:
31. case RETURN:
32. // comment out the following two lines to disable line-breaks
33. typedText += "\n";
34. break;
35. case ESC:
36. case DELETE:
37. break;
38. default:
39. typedText += key;
40. }
41. }
42. }
44. void randomNumber()
45. {
46. textFont(font,50);
47. int i=(int)random(0,10);
48. text(i,250,250);
49. }
Any help on this issue is highly appreciated thanks guys :)

Simple Processing problem

[4 Replies]
- 27-Dec-2012 01:02 PM
- Forum: Programming Questions
Hi guy I am new in this forum and I need some help. I have the following program. Now I need this program to work such that every time the user enters a number from 1-4, the last entry is replaced with the previous one. I know it can be done by using background(255) and therefore the screen is refreshed every time, but it is not a good method when you have other stuff rather than just the number...since everything will disappear.
Any help is appreciated :D
3. int leftmargin = 10;
4. String buff = "";
5. boolean cell_full = false;
7. void setup()
8. {
9. size(640, 360);
10. background(255);
11. textFont(loadFont("AngsanaNew-Bold-25.vlw"), 45);
13. }
15. void draw()
16. {
17. background(255);
19. if((millis() % 900) < 250)
20. { // at regular intervals the curser turns white so it looks like it is blinking
21. stroke(255);
22. }
23. else
24. { //else for the rest of the time the colour of the cursor is black
25. fill(255);
26. stroke(0);
27. }
29. float rPos; // x position of the cursor
30. rPos = textWidth(buff) + leftmargin; //textWidth(buff) is the length of all entered char PLUS the last margin
31. line(rPos, 9, rPos, 40);
32. println(textWidth(buff)); //Proof
34. fill(0);
36. pushMatrix();
37. translate(rPos,10+25);
38. char k;
39. for(int i = 0;i < buff.length(); i++) //buff.length always 1
40. {
41. k = buff.charAt(i);
42. translate(-textWidth(k),0); //-15,0
43. text(k,0,0);
44. }
45. popMatrix();
46. }
48. void keyPressed()
49. {
50. char k;
51. k = (char)key;
53. if(k==char(8))
54. {
55. if(buff.length()>0)
56. buff = buff.substring(1);
57. // cell_full=false;
60. }
62. if(cell_full==false)
63. {
64. if(k=='1')
65. buff=k+buff;
66. else if(k=='2')
67. buff=k+buff;
68. else if(k=='3')
69. buff=k+buff;
70. else if(k=='4')
71. buff=k+buff;
73. cell_full=true;
74. }
75. else
76. {
77. if(k=='1')
78. {
79. buff="";
80. buff=k+buff;
81. }
82. else if(k=='2')
83. {
84. buff="";
85. buff=k+buff;
86. }
87. else if(k=='3')
88. {
89. buff="";
90. buff=k+buff;
91. }
92. else if(k=='4')
93. {
94. buff="";
95. buff=k+buff;
96. }
97. }
99. }

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