Main code is :

There is the very simple code .

I 'have been spending the last days trying to solve this, I have a "ball" that circulate on the screen. When the ball is "offScreen", the ball's variables should be aded to another array (BouletteFixe) that will be displayed later on. Then, another ball will be circulated on a different direction and should be saved also.

I use append() in every manner (following Mrs Reas&Fry book aswell Mr Schiefman book). I feel stupid because the answer is probably obvious.

 

 

here is the code :

// Boulettes
//  avancer et garder la derniere
Boulette blt;
BouletteFixe[] bltfx = new BouletteFixe[1];

Boolean offScreen = false ;
float v_xpos, v_ypos,v_diam ;
color v_c ;

void setup() {
  size(400, 400, P3D);
  blt = new Boulette();
  bltfx[0] = new BouletteFixe(0.0,0.0,0.0,color(0));
}

void draw() {
  background(255);
  frameRate(5);
  for (int i=0; i<bltfx.length ; i++) {
    bltfx[i].display();
  }
  if (offScreen != true) {
    blt.move();
  }else {
    /// PROBLEMS
    BouletteFixe[] boul = new BouletteFixe(v_xpos,v_ypos,v_diam,v_c);
    bltfx =(BouletteFixe[])append(BouletteFixe,boul);
    // je mets la nouvelle boulette à la fin
    offScreen = true ;
  }
  blt.display();
}
//===================================
class Boulette {
  float []xpos = new float [1];
  float []ypos = new float [1];
  float []diam = new float [1];
  color []c = new color [1];
  float theta ;

 

  Boulette() {
    for (int i=0; i<xpos.length; i++) {
      xpos[i] = width/2;
      ypos[i]= height/2;
      diam [i]= 10.0 ;
      c [i] = 100 ;
    }
    theta = +2 ;
  }

  void move() {
    for (int i = 0; i < xpos.length-1 ; i ++) {
      xpos[i] = xpos[i+1] ;
      ypos[i] = ypos[i+1] ;
    }
    // si je suis offScreen
    if (xpos[xpos.length-1]+15>width || ypos[ypos.length-1]<0) {
      v_xpos=xpos[xpos.length-1];
      v_ypos=ypos[xpos.length-1];
      v_diam=diam[xpos.length-1];
      v_c = c[xpos.length-1] ;
      offScreen = true ;
    }
    else {//nouvelles valeurs
      xpos[xpos.length-1] = xpos[xpos.length-1]+15;
      ypos[ypos.length-1] = ypos[ypos.length-1]-theta ;
    }
  }

  void display() {
    //translate(width/2, height/2) ;
    for (int i = 0 ; i < xpos.length ; i ++) {
     // println("X "+xpos[i]);
     // println(ypos[i]);
     // println(offScreen);
      fill(100);
      stroke(0);
      ellipseMode(CENTER);
      ellipse(xpos[i], ypos[i], diam[i], diam[i]);
    }
  }
}
//==================================================================

// class BouletteFixe
class BouletteFixe {

  float xpos ;
  float ypos ;
  float diam ;
  color c ;

  BouletteFixe (float v_xpos, float v_ypos,float v_diam,color v_c) {
 
  }

  void display() {
    fill(100);
    stroke(0);
    ellipseMode(CENTER);
    for (int i=0; i<bltfx.length; i++) {
     // ellipse(xpos[i], ypos[i], diam[i], diam[i]);
     ellipse(xpos, ypos, diam, diam);
    }
  }
 
 // void update() {
   
 // }
 
}// fin boulfixe

 

 

 

I have been working on an example given on p307 of the wellknown Processing handbook.

Using a pre-registered text file( 1860 positions x / y), I reload it and get (of course) what I had registered before using the mouse.

How could I do to get the letters written slowly, handwritten like, instead of heaving all done at once?

EFRI

(Yes, I'm a newbi ! )

Thanks in advance.