Your shader cannot be used to render textured geometry, using default shader instead.

Contributed Library Questions

theviciou..

Your shader cannot be used to render textured geometry, using default shader instead.

in Contributed Library Questions • 1 year ago

When I run my GLSL shader using processing 2.0b3 and pshader, I get the following error;

Your shader cannot be used to render textured geometry, using default shader instead.

The shader runs about twice as slow compared to when I was using processing 1.5.1 with GLGraphics.

I have a feeling its trying to run two shaders at once, sacrificing performance.

Any thoughts?

Thanks!

Replies(2)

andres

Re: Your shader cannot be used to render textured geometry, using default shader instead.

1 year ago

Hello, you probably need to update the shader code you use in 1.5.1, since Processing 2.0 will expect the shader to have certain uniform and attribute variables in order to pass the geometry data to it. Please take a look at some notes here.

This applies only if you want to use your shader with the new shader() function. You can still do low-level OpenGL, in which case you don't have any restrictions in the shader code (see the LowLevelGL example included in Topics/Shaders).

theviciou..

Re: Your shader cannot be used to render textured geometry, using default shader instead.

1 year ago

Thank you for your quick response Andres!

Turns out that I was drawing some text after I called shader() which was resulting in that error.

After putting in a resetShader() after my rect(0,0,width,height) statement, the errors seemed to resolve.

I am however, still running into significant performance issues. I am getting about 50% of the frame rate or less compared to what I used to get in processing 1.5.1. I am not sure how to debug this problem....

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