Very basic String question

Programming Questions

latency

in Programming Questions • 1 year ago

Hi,

I'm writing my first Processing app and Strings aren't working the way I expect.

String s = "foo";
s += "bar";

I expect s to be "foobar", but whenever print s it displays as "foo";

I've also tried:

String s = "foo";
String t = s + "bar"; // same result

What am I missing?

Thanks,

Replies(2)

benja

Re: Very basic String question

1 year ago

I suppose this is not your whole code. The code you postet should work exactly as expected.

String s = "foo";
s += "bar";
println(s); // => prints "foobar"

I can only guess what you problem might be, maybe an issue with mixing global and local variables.
If you post the complete sketch, we could have another look into it.

latency

Re: Very basic String question

1 year ago

Thank you for the response benja!

In my case I was using readStringUntil("\n") and I didn't realize that the "\n" was included in the string. (my bad). Now I do:

g_distance = trim(g_distance) + "cm";

which works as expected.

Sorry for the silly mistake.

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