VectorField array question

Programming Questions

dennishusk

in Programming Questions • 2 years ago

I cannot make an array with locations for the vectors without using a for loop. Because of the rest of the code I need to draw all the vectors (calculates apparently of the canvas size). Is it possible to set some 'null' (how?)?

Thanks for any help!

for(i = 0; i < numVectors ; i++) {
int x = i % w;
int y = i / w;
int loc = int(x + y * w);
xoff += x*.0160 + .009;
yoff += y*.0160 + .009;
float angle = map(noise(xoff,yoff),0,1,0,TWO_PI);
field[loc] = new PVector(cos(angle), sin(angle));
}

I prefer something like this:

field[0] [ -0.3936499, -0.91926044, 0.0 ];
field[1] [ -0.38234037, -0.92402154, 0.0 ;]
field[2] [ -0.36286467, -0.93184185, 0.0 ];
etc.

But it doesn't work..

Replies(4)

PhiLho

Re: VectorField array question

2 years ago

I am sorry, but I didn't understand your question.

dennishusk

Re: VectorField array question

2 years ago

I'm sorry. The question is; how do I make an array (called field) where I can specify own locations into it. At the moment the loop fills the array with random values. I would like to make an array for drawing the vectors (locations given by myself).

thomas.di..

Re: Re: VectorField array question

2 years ago

i too have troubles understanding what exactly you need, so ill try something, maybe this will help:

// one version to initialize an 2-dimensional array
float values[][] =
{
{ 1.2, 2.2, 3.4},
{ 4.2, 5.2, 6.4},
{ 7.2, 8.2, 9.4},
{10.2, 11.2, 12.4},
{13.2, 14.2, 15.4}
};
println(values[1][2]);
// another version
float values_1[][] = new float[5][];
values_1[0] = new float[]{ 1.2, 2.2, 3.4};
values_1[1] = new float[]{ 4.2, 5.2, 6.4};
values_1[2] = new float[]{ 7.2, 8.2, 9.4};
values_1[3] = new float[]{10.2, 11.2, 12.4};
values_1[4] = new float[]{13.2, 14.2, 15.4};
println(values_1[1][2]);

PhiLho

Re: VectorField array question

2 years ago

PVector[] fields =
{
new PVector(-0.3936499, -0.91926044),
new PVector(-0.38234037, -0.92402154),
new PVector(-0.36286467, -0.93184185),
new PVector(-0.42, -0.11),
};