Unexpected token help

Programming Questions

bencakir

in Programming Questions • 11 months ago

I was messing around with switch statements when this occurred:

void setup() {
size(800, 800);
smooth();
background(255, 204, 0);
textFont(createFont("Serif", 25));
int iden = 0;
text("Press up to draw a shape, right to draw a name, and left to drag a name", 75, 75);
}
void keyPressed() {
if (key == CODED) {
if (keyCode == UP) {
int iden = 1;
}
else if (keyCode == RIGHT) {
int iden == 2;
}
else if (keyCode == LEFT) {
int iden == 3;
}
else {
int iden == 4;
}
}
void draw() {
switch(iden)
{
case 1:
break;
case 2:
break;
case 3:
break;
case 4:
break;
default:
println("WORK!!");
break;
}
}

I am getting a "unexpected token: int" at "int iden = 2"

Any suggestions?

Replies(5)

not_55

Re: Unexpected token help

11 months ago

int iden == 2; and subsequent similar lines are meant to be assignment not tests for equality, so...

int iden = 2;

Chrisir

Re: Unexpected token help

11 months ago

hello,

the int before iden says:

invent a new variable of that type int and name iden.

But you did that already with

int iden = 1;

in line 14.

so just have

iden = 2;

in line 17.

Moreover
Moreover: to define something, use =, to compare, use ==
so in line 17, 20, 23 only one =

Also
since you use iden also in setup and in draw etc.
what you want is

int iden = 0;

before setup() and not in setup (line 7).

Kill line 7 please.

Also line 14:

iden = 1;

without int. Since it is already defined in line 1.

Reason
Defining iden before setup() gives it global scope - meaning it is known throughout the program. Thus when you change it in keyPressed, draw() notices it.
Otherwise they would all be different local variables not having the same value (when you would use int in each function).

Greetings, Chrisir