double doesnt mean "2 decimal places" it means, its twice as big.
what you need it to use nfs() http://processing.org/reference/nfs_.html

would look like this in your code (change double to float )

1. void setup()
   {
     printLedger();
   }
   void printLedger()
   {
     float [] entry = {10.52, 1900.78, -234.78};
   for (int i = 0; i < entry.length; i++)
   {
     println(nfs(entry[i],0,2));
   }
   }
   
   

hey thanks, the only problem is that its for a problem set and it says to write a function that takes an array of double values as its argument and prints out the record.  so if thers anyway to leave it as a double and get the decimal places that would be good.

anyway, on to my next question.  along with the value i have to print a line that says whether its a deposit or withdrawal.  im guesing i have to make a variable with an if statement but i have no idea how.  any help would be appreciated

answering your second questions :

void setup()
{
  printLedger();
}
void printLedger()
{
  double [] entry = {10.52, 1900.78, -234.78};
for (int i = 0; i < entry.length; i++)
{
  if(entry[i]<0)println("Widthdrawal: ");
  else println("Deposit: ");
  println(nfs((float)entry[i],0,2));
 
 
}
}

thanks a lot man, works perfectly - i just have to get each statement and number on the same line, and add another statement that says the balance, well see how i do.

ok so i almost got it, sorry if this is trivial but im just curious as to what the best way to go about filling the balance is...right now i just have a filler equation.  i know its incorrect in determining the balance but i was wondering what i would replace it with.  heres the code

1. void setup()
   {
     printLedger();
   }
   
   void printLedger()
   {
     double [] entry = { 10.52, 1900.78, -234.78};
   for (int i = 0; i < entry.length; i++)
   {
     if(entry[i]>0)  println("Deposit" + nfs((float)entry[i],0,2) + "     Balance:" + nfs((float)(entry[i]+entry[i+1]),0,2));
     else println("Withdrawal " + nfs((float)entry[i],0,2) + "     Balance:" + nfs((float)(entry[i] + entry[i - 1]),0,2));
   }
   }
   

float balance = 0;
void setup()
{
  printLedger();
}

void printLedger()
{
  double [] entry = { 10.52, 1900.78, -234.78};
for (int i = 0; i < entry.length; i++)
{ balance += (float)entry[i];
  if(entry[i]>0)  println("Deposit" + nfs((float)entry[i],0,2) + "     Balance:" + balance);
  else println("Withdrawal " + nfs((float)entry[i],0,2) + "     Balance:" + balance);

}
}

Side note: it is OK for this toy, but a serious accounting application won't use floats (nor doubles) to do money computation! Decimal numbers often have no exact machine (binary) representation, so we often get rounding errors... Perfectly acceptable in a graphics application, unacceptable in accounting! So, either they use BCD or just count in centimes/cents/whatever smallest financial unit is used.