I am trying to send and receive 10 bit integers (the range of analogRead()) first from processing to Arduino and then arduino will reply back the same number to processing.
I am aware that Serial.write and Serial.read both send and receive 8 bit (1 Byte) values and I have that working. Now want to add 2 more bits to my Byte. I am sure I am not the first person to ask this.

The idea of bit-shifting is very interesting and I think it will solve my problem, however I need help on doing this; preferably an example code would be nice.
Or maybe help me build on top of the code I already have.

Thanks a bunch,

Processing

1. import processing.serial.*;
   Serial myPort;
   
   int inByte = 0;
   boolean proceed = false;
   boolean sending = true;
   
   void setup(){
     println(Serial.list());
     String portName = Serial.list()[0];
     // change [0] for the Arduino serial port
     myPort = new Serial(this, "COM5", 57600);
     myPort.clear();
    
   }
   
   void draw() {
     // first contact
     while (!proceed) {
       if ( myPort.available() > 0) {
         inByte = myPort.read();
         if (inByte == 'A') {
           println("Received " + inByte);
           myPort.clear();
           proceed = true;
         }
       }
     }
     // send and receive test
     while (proceed) {
       if (!sending) {
         if ( myPort.available() > 0) {
           inByte = myPort.read();
           println("Received " + inByte);
           myPort.clear();
           sending = true;
         }
       }
       if (sending){
         myPort.write(255);
         sending = false;
       }
     }
   }

Arduino

1. int inByte = 0;
   
   void setup() {
     // setup Serial comm with computer
     Serial.begin(57600);
     Serial.print('A'); // send letter "A"
   }
   
   void loop() {
     if (Serial.available() > 0) {
         inByte = Serial.read();
         Serial.write(inByte);
     }
   }